我有一個 2 個文本文件，我在其中存儲字典值并讀取它。所以我正在讀取 file1.txt 并將值存儲在 counter 變量中，對于 file2.txt 我將值存儲在 counter1 變量中。當我打印 counter 和 counter1 時，它會給出以下輸出。counter= {'laptop': 5, 'chair':6 , 'tv': 3}counter1= {'laptop': 2, 'chair': 4, 'tv': 4,'plant':2}p=len(counter) for z in range (0 ,p): if (list(counter.values())[v]!=list(counter1.values())[v]): print("Objects value on main list %s and Second List %s "%(list(counter.items())[v],list(counter1.items())[v])) else: pass v=v+1我想退掉這個：[{'laptop': 3}, {'chair': 2}, {'tv': 1}, {'plant': 2}]減去 counter 和 counter1 的值并打印結果。
2 回答
慕斯王
TA貢獻1864條經驗 獲得超2個贊
counter= {'laptop': 5, 'chair':6 , 'tv': 3}
counter1= {'laptop': 2, 'chair': 4, 'tv': 4,'plant':2}
out = [{key : abs(counter1[key] - counter[key])} if ((key in counter) and (key in counter1)) else {key : counter[key]} if (key in counter) else {key:counter1[key]} for key in set(counter.keys() + counter1.keys())]
print out
似乎可以在 1 行中完成，這應該可行。
一只甜甜圈
TA貢獻1836條經驗 獲得超5個贊
用這個
counter= {'laptop': 5, 'chair':6 , 'tv': 3}
counter1= {'laptop': 2, 'chair': 4, 'tv': 4,'plant':2}
out = []
for key, val in counter.items():
if key in counter1:
out.append({key:abs(val-counter1[key])})
else:
out.append({key:val})
for key, val in counter1.items():
if key not in counter:
out.append({key:val})
print(out)
添加回答
舉報
0/150
提交
取消