在這里，我試圖將 AJAX 調用作為單個函數進行，為此我將成功函數名稱作為函數參數傳遞給 AJAX 調用函數。我嘗試編寫以下函數：function ApiCallFunction(Datatext, ApiName, FunctionName) { $.ajax({ url: Apiurl + ApiName, type: "POST", data: Datatext, contentType: "application/json", dataType: "json", success: function(data) { var funname = FunctionName + '("' + data + '")'; eval(funname); }, error: function(error) { jsonValue = jQuery.parseJSON(error.responseText); ErrorWhileSave(jsonValue.Message); }, failure: function(response) { ErrorWhileSave(""); } });}函數調用：var datatext = { BillChild: {}, BillDate: "2018-07-23T08:35:32.319Z", EntryTime: "2018-07-23T08:35:32.319Z", ExitTime: "2018-07-23T08:35:32.319Z", TotalTime: "2018-07-23T08:35:32.319Z", Total: 0, OtherCharges: 0, Discount: 0, TaxableAmount: 0, TotalTax: 0, GrandTotal: 0, RoundOff: 0, NetAmount: 0, ByCash: 0, ByBank: 0, CashReceived: 0, BalanceReceivable: 0, FirmId: 0, UserId: 0, BillId: 35, CustomerId: 0, BranchId: 0, BillType: "string", BillNo: "string", PaymentType: "string", Notes: "string", TaxType: "string", BankId: "string", CreatedBy: "string", HostIp: "string", BranchTransfer: "string", ConsultId: 0, SearchKey: "string", Flag: "SELECTONE"};var Datatext = (JSON.stringify(datatext));ApiCallFunction(Datatext, "Bill_master", "ReturnFunction");我嘗試使用的 Success 函數是：function ReturnFunction(ReturnValue) { alert(data.data.Table1[0].BillId);}當我嘗試時，alert(ReturnValue)它顯示為object object. 我也試過ReturnValue.data.data.Table1[0].BillId仍然無法使用這些值。AJAX 調用成功，我從中獲得了價值，但我無法將結果 JSON 對象傳遞給其他函數。如何將 JSON 對象傳遞給其他函數？請幫我。
1 回答
largeQ
TA貢獻2039條經驗 獲得超8個贊
您可以通過不同的方式實現您的目標。
方法一簡單地將函數對象作為參數賦值
function ApiCallFunction(Datatext, ApiName, onSucess,onError) {
$.ajax({
url: Apiurl + ApiName,
type: "POST",
data: Datatext,
contentType: "application/json",
dataType: "json",
success: onSucess,
error: onError,
failure: function (response) {
ErrorWhileSave("");
}
});
}
并具有以下功能的實現：
function ReturnFunction(response){
//assuming that response is of JSON type
alert(response.data.Table1[0].BillId);
}
function myError(response){
console.log(JSON.parse(response.responseText).Message);
}
調用：
ApiCallFunction(DataText,"Bill_master",ReturnFunction,myError);
方法2如果你碰巧有一個字符串而不是函數對象
function ApiCallFunction(Datatext, ApiName, FunctionName) {
$.ajax({
url: Apiurl + ApiName,
type: "POST",
data: Datatext,
contentType: "application/json",
dataType: "json",
success: function (data) {
window[FunctionName].apply(this,data);
},
error: function (error) {
jsonValue = jQuery.parseJSON(error.responseText);
ErrorWhileSave(jsonValue.Message);
},
failure: function (response) {
ErrorWhileSave("");
}
});
}
調用：
ApiCallFunction(DataText,"Bill_master","ReturnFunction");
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