我無法解決語法錯誤。未關閉的字符串是我嘗試驗證它時的錯誤。function addNewCultureRow($row, $case, $specimen) { var $uniqueID = "." + $row + $case + "." + $specimen; var $tableRows = "<tr><td>" + $row + "<td><input id='localLevel" + $uniqueID + '" type="edit">' + "<td><input id='colony" + $uniqueID + '" type="edit">' + "<td><input id='description" + $uniqueID + '" type="edit">' + "<td><input id='oxidase" + $uniqueID + '" type="edit">' + "<td><input id='isolation1" + $uniqueID + '" type="edit">' + "<td><input id='isolation2" + $uniqueID + '" type="edit">' + "<td><input id='bioChemComments" + $uniqueID + '" type="edit">' + "<td><input id='IDMALDI" + $uniqueID + '" type="edit">' + "<td><input id='sensiID" + $uniqueID + '" type="edit">' + "<td><input id='organism-" + $case + "-" + $specimen + "544' type='select'>" + "<td><input id='localComments" + $uniqueID + '" type="edit">' + "<td><input id='comments-" + $case + "-" + $specimen + "-544-new' type='edit'>" + "<td><input id='result-" + $case + "-" + $specimen + "544-new' type='select'>"; return ($tableRows);}
無法解決此錯誤：未關閉的字符串
一只甜甜圈
2021-10-14 15:58:57
