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在python中按特定順序查找子字符串

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在python中按特定順序查找子字符串

Python

幕布斯6054654 2021-09-23 09:27:44

我有一長串字符串，其中包含按給定順序排列的感興趣的子字符串，但這里有一個在文本文件中使用句子的小例子：This is a long drawn out sentence needed to emphasize a topic I am trying to learn.It is new idea for me and I need your help with it please!Thank you so much in advance, I really appreciate it.從這個文本文件，我想找到同時包含任何句子"I"和"need"，但他們必須在出現的順序。因此，在這個例子中，'I'并且'need'都發生在第1句和第2句，但句子1他們是在錯誤的順序，所以我不想返回。我只想'I need'按順序返回第二句話。我用這個例子來識別子字符串，但我不知道如何只按順序找到它們：id1 = "I"id2 = "need"with open('fun.txt') as f: for line in f: if id1 and id2 in line: print(line[:-1])這將返回：This is a long drawn out sentence needed to emphasize a topic I am trying to learn.It is new idea for me and I need your help with it please!但我只想：It is new idea for me and I need your help with it please!謝謝！

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3 回答

慕蓋茨4494581

TA貢獻1850條經驗獲得超11個贊

您可以使用正則表達式來檢查這一點。一種可能的解決方案是：

id1 = "I"

id2 = "need"

regex = re.compile(r'^.*{}.*{}.*$'.format(id1, id2))

with open('fun.txt') as f:

for line in f:

if re.search(regex, line):

print(line[:-1])

反對回復 2021-09-23

慕無忌1623718

TA貢獻1744條經驗獲得超4個贊

您需要確定id2在該行的部分后 id1：

infile = [

"This is a long drawn out sentence needed to emphasize a topic I am trying to learn.",

"It is new idea for me and I need your help with it please!",

"Thank you so much in advance, I really appreciate it.",

]

id1 = "I"

id2 = "need"

for line in infile:

if id1 in line:

pos1 = line.index(id1)

if id2 in line[pos1+len(id1) :] :

print(line)

輸出：

It is new idea for me and I need your help with it please!

反對回復 2021-09-23

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在python中按特定順序查找子字符串

在python中按特定順序查找子字符串

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