我想根據category_id和vendor_id在數據庫中上傳多個圖像，包括使用 Code- igniter 進行驗證這里是屏幕截圖function upload_category_doc(){ $vendor_id = $this->input->post("vendor_id"); $category_id = $this->input->post("category_id"); $response = array(); if(isset($_FILES['category_doc']['name']) && $_FILES['category_doc']['name'] !=''){ $insertArr['category_doc']=$this->cat_upload('category_doc'); } $result = $this->providerapp_model->update_data("vbs_vendor_categories",$insertArr,array('vendor_id'=>$vendor_id,'category_id'=>$category_id)); $fields = "category_id,vendor_id,category_doc"; $sql1 = "SELECT $fields FROM vbs_vendor_categories vvc WHERE vvc.vendor_id=$vendor_id AND vvc.category_id=$category_id"; $vendor_cat_data = $this->db->query($sql1)->row(); if($result){ $response['data'] = $vendor_cat_data; $response['status'] = "success"; $response['message'] = "Category document update successfully"; }else{ $response['status'] = "fail"; $response['message'] = "Something went wrong"; } }和他的上傳功能上傳類別文件 function cat_upload($imagename){ $date = date('His'); $config['upload_path'] = 'uploads/category_doc'; $config['file_name'] = 'category_doc' . $date; $config['allowed_types'] = 'jpg|png|bmp|pdf|doc|svg'; $this->load->library('upload',$config); if (!$this->upload->do_upload($imagename)) { $upload_error = array('error' => $this->upload->display_errors()); } }}
2 回答
拉風的咖菲貓
TA貢獻1995條經驗 獲得超2個贊
$setting = $this->image_settings();
$this->load->library('upload', $setting);
$total = count(@$_FILES['image']['name']);
for($i=0; $i<$total; $i++)
{
$_FILES['userfile']['name']= @$_FILES['image']['name'][$i];
$_FILES['userfile']['type']= @$_FILES['image']['type'][$i];
$_FILES['userfile']['tmp_name']= @$_FILES['image']['tmp_name'][$i];
$_FILES['userfile']['error']= @$_FILES['image']['error'][$i];
$_FILES['userfile']['size']= @$_FILES['image']['size'][$i];
$this->upload->initialize($setting);
$this->upload->do_upload();
$actual_image_data = $this->upload->data();
if(!empty($actual_image_data['is_image'])) {
@$final_files_data[] = $actual_image_data['file_name'];
$img_data['image_path'] = @$final_files_data[$i];
$this->image_model->insert_image($img_data);
} else {
$response = [
'status' => FALSE,
'message' => 'Invalid file uploaded',
];
die(json_encode($response));
}
}
溫溫醬
TA貢獻1752條經驗 獲得超4個贊
你可以在 postman 的 name 字段中添加一個 file_name[] ，你可以從那里選擇多個文件
你必須通過你的 PHP 代碼循環上傳的文件
foreach ($_FILES['fil_name'] as $key => $value) {
// your stuff
}
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