public function getChildren($parent, $level=0,$getlevel=array()) { $criteria = new CDbCriteria; $criteria->condition='referred_by_user_id=:id'; $criteria->params=array(':id'=>$parent); $count = array(0=>0); $model = $this->findAll($criteria); // $levelcount = array(); $user=User::model()->findbypk(Yii::app()->user->id); if($user->level!=$level) { foreach ($model as $key) { $count[0]++; $index=1; // echo str_repeat(' — ', $level) . $key->name . "<br />"; $children= $this->getChildren($key->id, $level+1); // pr($children);die; foreach ($children as $child) { // pr($child); if ($child==0) continue; if (isset($count[$index])) $count[$index] += $child; else $count[$index] = $child; $index++; } } } return $count; }我只能輸出用戶數。如何獲取數組中每個級別的用戶 ID？
2 回答
一只甜甜圈
TA貢獻1836條經驗 獲得超5個贊
我前段時間做了類似的事情：
public static function getChildren($idParent) {
$elem = [];
$childrens = Arbol::model()->findAll("estado = 1 and id_parent = " . $idParent . ' ORDER BY level');
foreach ($childrens as $key => $child) {
$persona = Persona::model()->findbyPk($child->id_child);
if ((int) $persona->id_superior === $idParent) {
$nombre = explode(" ", $persona->nombres);
$elem[$key] = [
"id" => $persona->id_persona,
"image" => Yii::app()->baseUrl . '/images/user-icon' . ($persona->pago_inscripcion ? '-activo.png' : '.png'),
"text" => [
'title' => $nombre[0] . ' ' . substr($persona->apellido_paterno, 0, 1) . '.'
]
];
} else {
$keySUperior = array_search($persona->id_superior, array_column($elem, "id"));
if (is_int($keySUperior)) {
$elem[$keySUperior]["children"] = self::getChildren((int) $persona->id_superior);
}
}
}
return $elem;
}
我希望我能給你任何幫助
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