我有兩個實體類一：@Table(name = "package")public class Package {    @Id    @Column(name = "package_id", insertable = false, nullable = false)    private Long packageId;    @Column(name = "timestamp", nullable = false, updatable = false)    @Temporal(TemporalType.TIMESTAMP)    private Date timestamp;    @Column(name = "name", nullable = false)    private String name;    @ManyToOne(fetch = FetchType.LAZY, optional = false)    @JoinColumn(name = "queue_id",foreignKey=@ForeignKey(name = "package_queue_id_fk"))    private Queue Queue;@Column(name = "file_number", nullable = true)private Integer fileNumber;和@Table(name = "queue")public class Queue {    @Id    @Column(name = "queue_id", insertable = false, nullable = false)    private Integer queue;    @Column(name = "description", nullable = true)    private String description;    @Column(name = "name", nullable = false)    private String name;    @OneToMany(mappedBy = "Queue", fetch = FetchType.LAZY, cascade = { CascadeType.PERSIST, CascadeType.REFRESH })    @MapKeyColumn(name = "package_id")    private Set<Package> packages;我想根據 package.name 和 package.queue.queue_id 找到文件編號列表所以目前我只有一個條件（名稱），它看起來像這樣：public List<Integer> getAllFileNumbers(String fileName, Integer queueId) {    CriteriaBuilder cb = em.getCriteriaBuilder();    CriteriaQuery<Integer> query = cb.createQuery(Integer.class);    Root<Package> package = query.from(package.class);    query.select(package.get("fileNumber")).where(cb.equal(package.get("name"), fileName));    return em.createQuery(query).getResultList();}任何人都可以幫我添加另一個，除此之外，還要記住該值必須來自另一個實體。