我正在從書中自己學習 python 并解決問題。在一個問題中，用戶輸入跨年的一年中每個月的降雨量。我需要找到每年的平均降雨量（總和（每月降雨）/numb_months，以及那個時期的平均降雨量，例如兩年。在下面的代碼中，我可以獲得每年的平均值（我現在只使用了 3 個月而不是 12 個月，以避免繁瑣的輸入），但我不知道我需要在哪里放置一個累加器來計算在那段時間內的總降雨量，然后對其進行平均。感謝您的幫助。number_of_months = 3years_in_period = int(input("Please enter the number of years in the period. \n"))for year in range(years_in_period): yearly_rain = 0 print('Year', year+1) print('?????????????????') for month in range(number_of_months): print('Month', month+1, end='') monthly_rain = float(input("Please enter rainfall for this month: \n")) yearly_rain += monthly_rain average_yearly_rainfall = yearly_rain / number_of_months print("Average yearly rainfall of year ", year+1, " is ", average_yearly_rainfall) print("Year total rain is", yearly_rain) print()
1 回答
動漫人物
TA貢獻1815條經驗 獲得超10個贊
如果我明白你想要什么（計算這段時間內降雨量的絕對平均值），這應該可以解決問題：
number_of_months = 3
years_in_period = int(input("Please enter the number of years in the period. \n"))
total_rain = 0
for year in range(years_in_period):
yearly_rain = 0
print('Year', year+1)
print('?????????????????')
for month in range(number_of_months):
print('Month', month+1, end='')
monthly_rain = float(input("Please enter rainfall for this month: \n"))
yearly_rain += monthly_rain
total_rain += monthly_rain
average_yearly_rainfall = yearly_rain / number_of_months
print("Average yearly rainfall of year ", year+1, " is ", average_yearly_rainfall)
print("Year total rain is", yearly_rain)
print()
total_months = years_in_period * number_of_months
print("Absolute average of rain/month was", total_rain/total_months)
print("Absolute average of rain/year was", total_rain/years_in_period)
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