3 回答

TA貢獻2011條經驗 獲得超2個贊
這是一種numpy方法,首先按 排序Z,然后找到每個唯一X和Y對中的第一個,并建立索引:
a = np.array([[41.540588, -100.348335, 0.052785],
[41.540588, -100.348335, 0.053798],
[42.540588, -102.348335, 0.021798],
[42.540588, -102.348335, 0.022798],
[43.540588, -103.348335, 0.031798]])
# sort by Z
b = a[np.argsort(a[:,2])[::-1]]
# get first index for each unique x,y pair
u = np.unique(b[:,:2],return_index=True,axis=0)[1]
# index
c = b[u]
>>> c
array([[ 4.15405880e+01, -1.00348335e+02, 5.37980000e-02],
[ 4.25405880e+01, -1.02348335e+02, 2.27980000e-02],
[ 4.35405880e+01, -1.03348335e+02, 3.17980000e-02]])

TA貢獻1793條經驗 獲得超6個贊
如果您能夠使用pandas,則可以利用groupby和max
>>> pandas.DataFrame(arr).groupby([0,1], as_index=False).max().values
array([[ 4.15405880e+01, -1.00348335e+02, 5.37980000e-02],
[ 4.25405880e+01, -1.02348335e+02, 2.27980000e-02],
[ 4.35405880e+01, -1.03348335e+02, 3.17980000e-02]])

TA貢獻1936條經驗 獲得超7個贊
您可以通過排序和刪除重復項來使用 Pandas:
import pandas as pd
df = pd.DataFrame(arr)
res = df.sort_values(2, ascending=False)\
.drop_duplicates([0, 1])\
.sort_values(0).values
print(res)
array([[ 4.15405880e+01, -1.00348335e+02, 5.37980000e-02],
[ 4.25405880e+01, -1.02348335e+02, 2.27980000e-02],
[ 4.35405880e+01, -1.03348335e+02, 3.17980000e-02]])
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