我找不到一種方法來訪問我用來在我的 php 網絡表單上登錄的用戶名。我看過這些帖子，但我認為我的情況略有不同，因為它們都在頂部聲明了用戶名變量。我只是使用 sql 查詢登錄。這是登錄腳本<?php$uname=$_POST['uname'];$password=$_POST['password']; session_start();$con=mysqli_connect("localhost","root","g7trj98o6fyr5","login");//mysqli("localhost","username of database","password of database","database name")$result=mysqli_query($con,"SELECT * FROM `login_info` WHERE `uname`='$uname' && `password`='$password'");$count=mysqli_num_rows($result);if($count==1){    echo "Login success";    $_SESSION['log']=1;    header("refresh:2;url=welcome.php");}else{    echo "please fill proper details";    header("refresh:2;url=index.php");}?>我希望能夠使用當前登錄的用戶進行 if 檢查，以將他們與所有其他在線用戶區分開來。我有這個 if 檢查哪個應該只將編輯按鈕放在登錄的用戶旁邊。while($row = mysqli_fetch_array($result)){echo "<tr>";echo "<td>" . $row['uname'] . "</td>";echo "<td>" . $row['clickrate'] . "</td>";if($logedInUsername == $row['uname'])    echo "<td>" . $row['yourword'] . "<a href='edityourword.php?edit=$row[yourword]'> edit</a></td>";else    echo "<td>" . $row['yourword'] . "</td>";echo "</tr>";}echo "</table>";?>Welcome.php（if 語句所在的位置）<?phpfunction add_ant(&$connection){    mysqli_query($connection, "UPDATE `login_info` SET `clickrate`=`clickrate`+'1' WHERE `uname`='rvbvakama' && `password`='pass'");}session_start();if(isset($_SESSION['log'])){$_SESSION['uname'] = $_POST['uname'];echo "<script type='text/javascript'>alert('$logedInUsername');</script>";$con=mysqli_connect("localhost","root","pass","login"); //mysqli("localhost","username of database","password of database","database name")if(array_key_exists('add',$_POST)){   add_ant($con);}$result = mysqli_query($con,"SELECT * FROM login_info");if (!$result) {    printf("Error: %s\n", mysqli_error($con));    exit();}echo "<table border='1'><tr><th>username</th><th>clickrate</th><th>yourword</th></tr>";