我正在嘗試使用 PHP 代碼為電報做 BOT?；旧嫌脩舯仨氃诓迦胫g進行選擇：1）姓名 2）姓氏 3）地址選擇姓氏，他必須寫下他的姓氏，我想將其存儲到變量中，但是，如果我使用，$update = file_get_contents('php://input')我總是讀“姓氏”（這是用戶的第一個輸入）所以我認為我的問題是：如何file_get_contents('php://input')在我的程序的特定“時刻”中更改內容？請閱讀我的代碼以獲取更多詳細信息，非常感謝！??！    <?php$botToken = "MYTOKEN"; //token $website = "https://api.telegram.org/bot".$botToken;$update = file_get_contents('php://input'); //updates from telegram (JSON format)$update = json_decode($update, TRUE); $chatId = $update['message']['from']['id']; $text = $update['message']['text']; switch($text)    {    case "name";    sendMessage ($chatId,"You write name");    break;    case "surname";    sendMessage ($chatId,"You write surname");     sendMessage ($chatId,"Insert your surname");                 /* here is my problem: what i have to do to "read" what the                 user write now? i want to store his surname into a new                 variable*/    break;    case "address";    sendMessage ($chatId,"You write address");    break;     default;    sendMessage ($chatId,"You don't write a valid command");    break;         }function sendMessage($chatId,$text)    {        $url = $GLOBALS[website]."/sendMessage? chat_id=$chatId&text=".urlencode($text);        file_get_contents($url);    }?>