我正在嘗試編寫一些 PHP 代碼,以便當用戶輸入報價時,應用程序會查看報價表,計算當年提出的報價數量,然后將計數加 1,最終結果是提供一個那一年的唯一和連續報價編號。格式應該是 Q/YY/sequential number//Insert New Q Reference //set standards $time=strtotime($values['QuoteDate']); $LongYear=date("Y",$time); $ShortYear=date("y",$time); //Get current number quotes for the year which quote was issued global $dal; $dal_table = $dal->Table("quotations"); if ($values["QuoteDate"]) { $rstmp = CustomQuery("select count(*) as count1 from quotations where '$LongYear' = ".$LongYear); $datatmp = db_fetch_array($rstmp); $count_value = 0; if ($datatmp["count1"]) $count_value = $datatmp["count1"]; $values['QuoteReference'] = 'Q/'.$ShortYear.'/'.str_pad(($count_value+1), 4, '0', STR_PAD_LEFT); }我遇到的問題是代碼只是返回總序列號 + 1 并且沒有考慮年份的計數!看下面的截圖,2018應該是Q/18/0001
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夢里花落0921
TA貢獻1772條經驗 獲得超6個贊
在您的查詢中,您正在比較
'$LongYear' = ".$LongYear
這將永遠成功。您應該從列的值中比較年份:
YEAR(QuoteDate) = ".$LongYear
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