我是 php 新手，我需要上傳分配給文件的隨機名稱的文件，并使用隨機名稱存儲該文件以上傳文件夾并將該隨機名稱存儲到 mysql 數據庫中。 $pic_file1 = $this->input->post('pic_file'); $pic_file1 = str_replace( "\\", '/', $pic_file1); $filename = time().basename($pic_file1); $config['upload_path'] = './uploads/'; $config['allowed_types'] = 'gif|jpg|png'; $config['max_size'] = 1000; //$config['encrypt_name'] = TRUE; // $config['overwrite'] = FALSE; $config['file_name'] = $filename; $this->load->library('upload', $config); $this->upload->initialize($config); if ( ! $this->upload->do_upload('pic_file')) { $error = array('error' => $this->upload->display_errors()); print_r($error); } else { $data = array('upload_data' => $this->upload->data()); // print_r($data); }
3 回答
幕布斯6054654
TA貢獻1876條經驗 獲得超7個贊
$pic_file1 = $this->input->post('pic_file');
$config['upload_path'] = './uploads/';
$config['allowed_types'] = 'gif|jpg|png';
$config['max_size'] = 1000;
//$config['encrypt_name'] = TRUE;
// $config['overwrite'] = FALSE;
$config['file_name'] = time();
$this->load->library('upload', $config);
$this->upload->initialize($config);
if ( ! $this->upload->do_upload('pic_file'))
{
$error = array('error' => $this->upload->display_errors());
print_r($error);
}
else
{
$data = array('upload_data' => $this->upload->data());
// print_r($data);
}
catspeake
TA貢獻1111條經驗 獲得超0個贊
上面的代碼與任何框架相關。如果您是 php 新手，請嘗試使用下面提到的簡單代碼。
$target_dir = "/var/www/html/uploads/"; // this is base path
$imageFileType = strtolower(pathinfo(basename($_FILES["pic_file"]["name"]),PATHINFO_EXTENSION));
$filename = time().$imageFileType; //save this file name to database $filename
$target_file = $target_dir.$filename
if(isset($_POST["submit"])) {
$check = getimagesize($_FILES["pic_file"]["tmp_name"]);
if($check !== false) {
if (move_uploaded_file($_FILES["pic_file"]["tmp_name"], $target_file)) {
echo "The file ". basename( $_FILES["pic_file"]["name"]). " has been uploaded on : ".$target_file;
} else {
echo "Sorry, there was an error uploading your file.";
}
} else {
echo "File is not an image.";
}
}
如果您還需要 HTML，請告訴我我會提供。
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