這段代碼失敗了我在數據庫中有一個現有的版本化值，我使用 獲取該值entity manager.find并在實體上設置。VersionEntity version = entityManager.find(VersionEntity.class, 1);entities.forEach(__ -> __.setVersion(version));entities.forEach(entityManager::persist);entityManager.flush();我專門查找并分配版本 1，那么為什么它甚至會嘗試使用版本 2。我什至嘗試過merge，但沒有奏效。我的屬性顯然是錯誤的/不正確的。刷新失敗本地異常堆棧：異常 [EclipseLink-4002]（Eclipse 持久性服務 - 2.7.1.qualifier）：org.eclipse.persistence.exceptions.DatabaseException 內部異常：org.postgresql.util.PSQLException：錯誤：插入或更新表“ t_quality_measurement”違反外鍵約束“fk_t_quality_measurement_version” 詳細信息：表“t_version”中不存在鍵（版本）=（2）。錯誤代碼：0 調用：INSERT INTO T_QUALITY_MEASUREMENT (BRAND, DATE, KPICODE, KPICOMPAREVW, KPICOMPAREWT, KPIVALUE, ORGANISATIONUNIT, PHASE, PLANT, SERIES, SIGNALCOLOR, TECHNOLOGY, TEMPORALUNIT, (?, S?) ?, ?, ?, ?, ?, ?, ?, ?, ?) bind => [14 個參數綁定] 查詢：當我專門查找 1 時，我不確定為什么它會嘗試使用 2。@Entity@Table(name = "T_QUALITY_MEASUREMENT")public class QualityMeasurementEntity extends Versioned implements Serializable {    @Id    @GeneratedValue(strategy = GenerationType.IDENTITY)    @Column(columnDefinition = "serial")    private Integer id;    @Column(length = 100)    private String series;版本化看起來像這樣@MappedSuperclasspublic abstract class Versioned {    @ManyToOne    @JoinColumn(name = "version", insertable = false, updatable = false)    protected VersionEntity version = null;    public VersionEntity getVersion() { return version; }    public void setVersion(VersionEntity version) { this.version = version; }}和版本實體。@Entity@Table(name = "T_VERSION", indexes = {        @Index(name = "pk_version", columnList = "id", unique = true)})@NamedQuery(name = "Version.findById", query = "SELECT v FROM VersionEntity v WHERE v.id = :id")public class VersionEntity {    @Id    @GeneratedValue(strategy = GenerationType.IDENTITY)    @Column(columnDefinition = "serial")    private Integer id;    @Column(name = "CREATED")    private LocalDateTime created;