我有一個字符串，其中包含代表多邊形的坐標列表。在這個列表中，每個多邊形都有相同的起始和結束坐標。我需要將每個多邊形放在單獨的字符串（或列表）中。' 17.17165756225586 -28.102264404296875，17.184370040893555 -28.200496673583984,17.1986083984375 -28.223613739013672，17.17165756225586 -28.102264404296875， 28.865726470947266 -28.761619567871094，28.80694007873535 -28.75750160217285,28.792499542236328 -28.706947326660156，28.865726470947266 -28.761619567871094 '所以從這個簡單的例子中，我需要有兩個元素：一個= ' 17.17165756225586 -28.102264404296875，17.184370040893555 -28.200496673583984,17.1986083984375 -28.223613739013672，17.17165756225586 -28.102264404296875 '兩= ' 28.865726470947266 -28.761619567871094，28.80694007873535 -28.75750160217285,28.792499542236328 -28.706947326660156，28.865726470947266 -28.761619567871094 ' *字符串中可以有更多的多邊形，每個多邊形都需要分開。我只能為此使用標準的 python 庫
3 回答
泛舟湖上清波郎朗
TA貢獻1818條經驗 獲得超3個贊
由于您的輸入已經是一個字符串（而且您的預期結果也是？），您可以使用帶有反向引用的正則表達式 來嘗試這個超級懶惰的解決方案(([^,]+).*\2)。這里，[^,]+是第一個坐標對，.*其他對，\2再次是第一對。
>>> s = '17.17165756225586 -28.102264404296875,17.184370040893555 -28.200496673583984,17.1986083984375 -28.223613739013672,17.17165756225586 -28.102264404296875, 28.865726470947266 -28.761619567871094,28.80694007873535 -28.75750160217285,28.792499542236328 -28.706947326660156, 28.865726470947266 -28.761619567871094'
>>> re.findall(r"(([^,]+).*\2)", s)
[('17.17165756225586 -28.102264404296875,17.184370040893555 -28.200496673583984,17.1986083984375 -28.223613739013672,17.17165756225586 -28.102264404296875',
'17.17165756225586 -28.102264404296875'),
(' 28.865726470947266 -28.761619567871094,28.80694007873535 -28.75750160217285,28.792499542236328 -28.706947326660156, 28.865726470947266 -28.761619567871094',
' 28.865726470947266 -28.761619567871094')]
或者使用finditer并獲取group直接獲取字符串列表：
>>> [m.group() for m in re.finditer(r"(([^,]+).*\2)", s)]
['17.17165756225586 -28.102264404296875,17.184370040893555 -28.200496673583984,17.1986083984375 -28.223613739013672,17.17165756225586 -28.102264404296875',
' 28.865726470947266 -28.761619567871094,28.80694007873535 -28.75750160217285,28.792499542236328 -28.706947326660156, 28.865726470947266 -28.761619567871094']
一些后期處理后，獲得對數字的實際列表（與_作為的結果findall;對于finditer刪除[0]）：
>>> [[tuple(map(float, y.split())) for y in x[0].split(",")] for x in _]
[[(17.17165756225586, -28.102264404296875),
(17.184370040893555, -28.200496673583984),
(17.1986083984375, -28.223613739013672),
(17.17165756225586, -28.102264404296875)],
[(28.865726470947266, -28.761619567871094),
(28.80694007873535, -28.75750160217285),
(28.792499542236328, -28.706947326660156),
(28.865726470947266, -28.761619567871094)]]
對于更長的字符串，這可能不是最快的解決方案，不過我沒有計時。
狐的傳說
TA貢獻1804條經驗 獲得超3個贊
s='17.17165756225586 -28.102264404296875,17.184370040893555 -28.200496673583984,17.1986083984375 -28.223613739013672,17.17165756225586 -28.102264404296875, 28.865726470947266 -28.761619567871094,28.80694007873535 -28.75750160217285,28.792499542236328 -28.706947326660156, 28.865726470947266 -28.761619567871094'
#convert the input in a list of points
coordinates = [tuple(map(float,el.split())) for el in s.split(",")]
polygons = []
#find the polygons
while coordinates:
ind = coordinates[1:].index(coordinates[0])
polygons.append(coordinates[0:ind+2])
coordinates = coordinates[ind+2:]
#output
[(17.17165756225586, -28.102264404296875), (17.184370040893555, -28.200496673583984), (17.1986083984375, -28.223613739013672), (17.17165756225586, -28.102264404296875)]
[(28.865726470947266, -28.761619567871094), (28.80694007873535, -28.75750160217285), (28.792499542236328, -28.706947326660156), (28.865726470947266, -28.761619567871094)]
倚天杖
TA貢獻1828條經驗 獲得超3個贊
這是一個相當丑陋但有效的解決方案，只是將明顯的方法真正放入代碼中。
# Note that your string has inconsistent separators -- sometimes ',', sometimes ', '.
# I'm going to separate on `,` and not worry about it -- you need to work out
# what the correct separator is.
s = '17.17165756225586 -28.102264404296875,17.184370040893555 -28.200496673583984,17.1986083984375 -28.223613739013672,17.17165756225586 -28.102264404296875, 28.865726470947266 -28.761619567871094,28.80694007873535 -28.75750160217285,28.792499542236328 -28.706947326660156, 28.865726470947266 -28.761619567871094'
coordinates = s.split(',')
polygon = []
polygons = []
new = True
for coordinate in coordinates:
polygon.append(coordinate)
if new:
start = coordinate
new = False
elif coordinate == start:
polygons.append(polygon)
polygon = []
new = True
result = [",".join(polygon) for polygon in polygons]
print(result)
Out:
['17.17165756225586 -28.102264404296875,17.184370040893555 -28.200496673583984,17.1986083984375 -28.223613739013672,17.17165756225586 -28.102264404296875', ' 28.865726470947266 -28.761619567871094,28.80694007873535 -28.75750160217285,28.792499542236328 -28.706947326660156, 28.865726470947266 -28.761619567871094']
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