我想檢查用戶的輸入并檢查輸入是否被接受。該方法稱為“ check_input”，我在“ running”方法的第三行中稱為此方法。我給它傳遞了一個字符串和布爾變量。然后我想返回 inputAccepted 值，然后根據它的值對它做一些事情。我已經使用了斷點，并且bool本身已正確更改，但是當代碼離開'check_input'方法時，bool'inputAccepted'被遺忘了。我究竟做錯了什么？我的理論是 bool 在方法之外無法訪問？import randomimport collectionsimport recodeLength = 4guessesRemaining = 10inputAccepted = FalsewelcomeMessage = 'Welcome to Mastermind. Try and guess the code by using the following letters:\n\nA B C D E F \n\nThe code will NOT contain more than 1 instance of a letter.\n\nAfter you have entered your guess press the "ENTER" key.\nYou have a total of'print(welcomeMessage, guessesRemaining, 'guesses.\n')def gen_code(codeLength):    symbols = ('ABCDEF')    code = random.sample(symbols, k=codeLength)    return str(code)code = gen_code(codeLength)print(code)counted = collections.Counter(code)def check_input(guess, inputAccepted):    if not re.match("[A-F]", guess): #Only accepts the letters from A-F        print("Please only use the letters 'ABCDEF.'")        inputAccepted = False        return (guess, inputAccepted)    else:        inputAccepted = True        return (guess, inputAccepted)def running():    guess = input() #Sets the guess variable to what the user has inputted    guess = guess.upper() #Converts the guess to uppercase    check_input(guess, inputAccepted) #Checks if the letter the user put in is valid    print(guess)    print(inputAccepted)    if inputAccepted == True:        guessCount = collections.Counter(trueGuess)        close = sum(min(counted[k], guessCount[k]) for k in counted)        exact = sum(a == b for a,b in zip(code, guess))        close -= exact        print('\n','Exact: {}. Close: {}. '.format(exact,close))        return exact != codeLength    else:        print("Input wasnt accepted")