問題：我想將2個關聯數組組合成一個。要鏈接這些陣列，兩個中都存在ID密鑰。輸入：要使用api調用來檢索我的聯系人，我必須執行2個請求：首先使用ID檢索聯系人，并通過電子郵件發送地址，然后獲取一些信息，例如姓名，城市等。第一個返回這樣的數組：$contactArray = array( array( "CreatedAt" => "2019-04-12T11:53:26Z", "DeliveredCount" => 0, "Email" => "[email protected]", "ExclusionFromCampaignsUpdatedAt" => "2019-04-28T09:21:35Z", "ID" => 1864410583, "IsExcludedFromCampaigns" => false, "IsOptInPending" => false, "IsSpamComplaining" => false, "LastActivityAt" => "2019-04-28T09:21:35Z", "LastUpdateAt" => "2019-04-28T09:21:35Z", "Name" => "", "UnsubscribedAt" => "", "UnsubscribedBy" => "" ), array( "CreatedAt" => "2019-04-12T12:39:30Z", "DeliveredCount" => 0, "Email" => "[email protected]", "ExclusionFromCampaignsUpdatedAt" => "", "ID" => 1864410588, "IsExcludedFromCampaigns" => false, "IsOptInPending" => false, "IsSpamComplaining" => false, "LastActivityAt" => "2019-04-12T12:39:30Z", "LastUpdateAt" => "2019-04-12T12:39:30Z", "Name" => "", "UnsubscribedAt" => "", "UnsubscribedBy" => "" ));第二次調用，返回一個類似的數組$contactDataArray = array( array( "ContactID" => 1864410583, "Data" => array( array( "Name" => "firstname", "Value" => "Mark" ), array( "Name" => "city", "Value" => "Miami" ), array( "Name" => "name", "Value" => "Terry" ), array( "Name" => "phone", "Value" => "555-5555" ) ), "ID" => 1864410583 ),在中$contactArray，ID鍵與ContactID鍵和ID中的ID鍵匹配$contactDataArray
3 回答
慕村9548890
TA貢獻1884條經驗 獲得超4個贊
對于PHP> = 7.1，可以使用list（）使用數組解構
<?php
$output = [];
foreach ($contactDataArray as [
'ID' => $id,
'Data' => [
['Name' => $firstnameKey, 'Value' => $firstnameValue],
['Name' => $cityKey, 'Value' => $cityValue],
['Name' => $nameKey, 'Value' => $nameValue],
['Name' => $phoneKey, 'Value' => $phoneValue]
]
]) {
$output[] = [
"Email" => $contactArray[array_search($id, array_column($contactArray, 'ID'))]['Email'],
"ID" => $id,
$firstnameKey => $firstnameValue,
$cityKey => $cityValue,
$nameKey => $nameValue,
$phoneKey => $phoneValue
];
}
var_dump($output);
米脂
TA貢獻1836條經驗 獲得超3個贊
您可以使用foreach做到這一點，
$result = [];
foreach ($contactDataArray as $key => $value) {
$ids = array_column($contactArray, "ID"); // fetching all values from contactArray
if (!empty(array_intersect([$value['ContactID'], $value['ID']], $ids))) { // checking if both satisfy the condition
$result[$key] = array_column($value['Data'], 'Value', 'Name'); // combining name and value
// searchng for key with matched ContactID
$result[$key]['Email'] = $contactArray[array_search($value["ContactID"], $ids)]['Email'];
$result[$key]['ID'] = $value["ContactID"];
}
}
演示。
回首憶惘然
TA貢獻1847條經驗 獲得超11個贊
你可以試一下嗎？
$output = [];
for($i = 0; $i < count($contactDataArray); $i++) {
$arrIDandEmail = [
'Email' => isset($contactArray[$i]['Email']) ? $contactArray[$i]['Email'] : '',
'ID' => isset($contactDataArray[$i]['ID']) ? $contactDataArray[$i]['ID'] : ''
];
$arrData = array_column($contactDataArray[$i]["Data"], "Value", "Name");
$newArray = array_merge($arrIDandEmail, $arrData);
$output[] = $newArray;
}
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