我正在嘗試創建一個程序，該程序可以找到輸入的n個數字的平均值，但是我無法使遞歸正常工作。該程序可以工作，但在我希望的時候不會退出while語句。print("This program 'is' designed to find the average of n numbers you input\n") #print statement that introduces the average findercounter = 0 #this counter will count how many numbers the user has inserted into the program and will be used as denominator sum_of_numbers = 0 #this number is set as 0 as currently the sum is 0, as more numbers are inputed, they will be added togetherfirst_question = input('''Would you like to enter a number? Type "yes" if you do, and "no" if you don't. \n\n''') #takes input of yes or no to see whether user wants to find average of numberswhile first_question == "yes" : ent_num = int(input("Enter your number here:")) sum_of_numbers = sum_of_numbers + ent_num counter = counter + 1 second_question = input('''Would you like to enter another number after this? Type "yes" if you do, and "no" if you don't. \n''') while second_question == "yes" : ent_num = int(input("Enter your next number here: ")) sum_of_numbers = sum_of_numbers + ent_num counter = counter + 1 else : print("Your average is " + str(sum_of_numbers/counter))有人可以幫我解決嗎？我不能使用諸如try或eval之類的功能，也不能使用它的所有真正基本的東西，例如我上課的第三天
3 回答
皈依舞
TA貢獻1851條經驗 獲得超3個贊
您只需要一個循環即可工作。只需問您一個問題，獲取輸入，然后循環即可。當您輸入no時，循環將退出并計算您的平均值。
print("This program 'is' designed to find the average of n numbers you input\n") #print statement that introduces the average finder
counter = 0 #this counter will count how many numbers the user has inserted into the program and will be used as denominator
sum_of_numbers = 0 #this number is set as 0 as currently the sum is 0, as more numbers are inputed, they will be added together
first_question = input('''Would you like to enter a number? Type "yes" if you do, and "no" if you don't. \n\n''') #takes input of yes or no to see whether user wants to find average of numbers
while first_question == "yes" :
ent_num = int(input("Enter your number here:"))
sum_of_numbers = sum_of_numbers + ent_num
counter = counter + 1
first_question = input('''Would you like to enter another number after this? Type "yes" if you do, and "no" if you don't. \n''')
print("Your average is " + str(sum_of_numbers/counter))
千萬里不及你
TA貢獻1784條經驗 獲得超9個贊
您的代碼足夠簡潔，無法對其進行注釋。畢竟是蟒蛇！
這是一個簡短的工作版本：
print("This program 'is' designed to find the average of n numbers you input\n")
first_question = 'Would you like to enter a number? (type "yes" if you do)\n\n'
second_question = 'Would you like to enter another number after this? (type "yes" if you do)\n'
sum_of_numbers = 0
counter = 0
if input(first_question) == "yes" :
sum_of_numbers += int(input("Enter your number here:"))
counter += 1
while input(second_question) == "yes" :
sum_of_numbers += int(input("Enter your next number here: "))
counter += 1
print("Your average is " + str(sum_of_numbers/counter))
嗶嗶one
TA貢獻1854條經驗 獲得超8個贊
first_question永遠不會更改，并且您在完成第二個練習后還應該進行數學運算。由于您將輸出分配給second_question，因此first_question始終保持“是”。由于您永遠不會再簡單地詢問first_question：
print("This program 'is' designed to find the average of n numbers you input\n") #print statement that introduces the average finder
counter = 0 #this counter will count how many numbers the user has inserted into the program and will be used as denominator
sum_of_numbers = 0 #this number is set as 0 as currently the sum is 0, as more numbers are inputed, they will be added together
first_question = input('''Would you like to enter a number? Type "yes" if you do, and "no" if you don't. \n\n''')
#takes input of yes or no to see whether user wants to find average of numbers.
if first_question == "yes" :
ent_num = int(input("Enter your number here:"))
sum_of_numbers = sum_of_numbers + ent_num
counter = counter + 1
second_question = input('''Would you like to enter another number after this? Type "yes" if you do, and "no" if you don't. \n''')
while second_question == "yes" :
ent_num = int(input("Enter your next number here: "))
sum_of_numbers = sum_of_numbers + ent_num
counter = counter + 1
print("Your average is " + str(sum_of_numbers/counter))
else :
print("Well if you're just going to answer no off the bat why did you bother running me\n");
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