3 回答

TA貢獻1831條經驗 獲得超10個贊
我提出了一個略有不同的解決方案。
假設我們有比簡單[String: Any]解析還要多的東西:Any可能是數組,嵌套字典或數組字典。
像這樣:
var json = """
{
"id": 12345,
"name": "Giuseppe",
"last_name": "Lanza",
"age": 31,
"happy": true,
"rate": 1.5,
"classes": ["maths", "phisics"],
"dogs": [
{
"name": "Gala",
"age": 1
}, {
"name": "Aria",
"age": 3
}
]
}
"""
好吧,這是我的解決方案:
public struct AnyDecodable: Decodable {
public var value: Any
private struct CodingKeys: CodingKey {
var stringValue: String
var intValue: Int?
init?(intValue: Int) {
self.stringValue = "\(intValue)"
self.intValue = intValue
}
init?(stringValue: String) { self.stringValue = stringValue }
}
public init(from decoder: Decoder) throws {
if let container = try? decoder.container(keyedBy: CodingKeys.self) {
var result = [String: Any]()
try container.allKeys.forEach { (key) throws in
result[key.stringValue] = try container.decode(AnyDecodable.self, forKey: key).value
}
value = result
} else if var container = try? decoder.unkeyedContainer() {
var result = [Any]()
while !container.isAtEnd {
result.append(try container.decode(AnyDecodable.self).value)
}
value = result
} else if let container = try? decoder.singleValueContainer() {
if let intVal = try? container.decode(Int.self) {
value = intVal
} else if let doubleVal = try? container.decode(Double.self) {
value = doubleVal
} else if let boolVal = try? container.decode(Bool.self) {
value = boolVal
} else if let stringVal = try? container.decode(String.self) {
value = stringVal
} else {
throw DecodingError.dataCorruptedError(in: container, debugDescription: "the container contains nothing serialisable")
}
} else {
throw DecodingError.dataCorrupted(DecodingError.Context(codingPath: decoder.codingPath, debugDescription: "Could not serialise"))
}
}
}
嘗試使用
let stud = try! JSONDecoder().decode(AnyDecodable.self, from: jsonData).value as! [String: Any]
print(stud)
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