3 回答

TA貢獻1946條經驗 獲得超3個贊
Jean Logeart的特別版答案
public static int[] regExIndex(String pattern, String text, Integer fromIndex){
Matcher matcher = Pattern.compile(pattern).matcher(text);
if ( ( fromIndex != null && matcher.find(fromIndex) ) || matcher.find()) {
return new int[]{matcher.start(), matcher.end()};
}
return new int[]{-1, -1};
}

TA貢獻1852條經驗 獲得超1個贊
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class RegexMatches
{
public static void main( String args[] ){
// String to be scanned to find the pattern.
String line = "This order was places for QT3000! OK?";
String pattern = "(.*)(\\d+)(.*)";
// Create a Pattern object
Pattern r = Pattern.compile(pattern);
// Now create matcher object.
Matcher m = r.matcher(line);
if (m.find( )) {
System.out.println("Found value: " + m.group(0) );
System.out.println("Found value: " + m.group(1) );
System.out.println("Found value: " + m.group(2) );
} else {
System.out.println("NO MATCH");
}
}
}
結果
Found value: This order was places for QT3000! OK?
Found value: This order was places for QT300
Found value: 0
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