我正在做具有示例代碼片段的Rust by Example教程：// Vec examplelet vec1 = vec![1, 2, 3];let vec2 = vec![4, 5, 6];// `iter()` for vecs yields `&i32`. Destructure to `i32`.println!("2 in vec1: {}", vec1.iter()     .any(|&x| x == 2));// `into_iter()` for vecs yields `i32`. No destructuring required.println!("2 in vec2: {}", vec2.into_iter().any(| x| x == 2));// Array examplelet array1 = [1, 2, 3];let array2 = [4, 5, 6];// `iter()` for arrays yields `&i32`.println!("2 in array1: {}", array1.iter()     .any(|&x| x == 2));// `into_iter()` for arrays unusually yields `&i32`.println!("2 in array2: {}", array2.into_iter().any(|&x| x == 2));我非常困惑-對于Vec從iteryields引用返回的迭代器和從into_iteryields值返回的迭代器，但是對于數組，這些迭代器是相同的嗎？這兩種方法的用例/ API是什么？