TA貢獻1806條經驗 獲得超5個贊
對于整數：
var x=12345678;
x=x.toString();
var lastThree = x.substring(x.length-3);
var otherNumbers = x.substring(0,x.length-3);
if(otherNumbers != '')
lastThree = ',' + lastThree;
var res = otherNumbers.replace(/\B(?=(\d{2})+(?!\d))/g, ",") + lastThree;
alert(res);
對于浮點數：
var x=12345652457.557;
x=x.toString();
var afterPoint = '';
if(x.indexOf('.') > 0)
afterPoint = x.substring(x.indexOf('.'),x.length);
x = Math.floor(x);
x=x.toString();
var lastThree = x.substring(x.length-3);
var otherNumbers = x.substring(0,x.length-3);
if(otherNumbers != '')
lastThree = ',' + lastThree;
var res = otherNumbers.replace(/\B(?=(\d{2})+(?!\d))/g, ",") + lastThree + afterPoint;
alert(res);
TA貢獻1834條經驗 獲得超8個贊
我遲到了，但我想這會有所幫助的:)
您可以使用Number.prototype.toLocaleString（）
句法
numObj.toLocaleString([locales [, options]])
var number = 123456.789;
// India uses thousands/lakh/crore separators
document.getElementById('result').innerHTML = number.toLocaleString('en-IN');
// → 1,23,456.789
document.getElementById('result1').innerHTML = number.toLocaleString('en-IN', {
maximumFractionDigits: 2,
style: 'currency',
currency: 'INR'
});
// → Rs.123,456.79
<div id="result"></div>
<div id="result1"></div>
TA貢獻1895條經驗 獲得超7個贊
對于整數，不需要其他操作。
這將匹配末尾的每個數字，其后具有1個或多個雙位數字模式，并將其替換為自身+“，”：
"125465778".replace(/(\d)(?=(\d\d)+$)/g, "$1,");
-> "1,25,46,57,78"
但是，由于我們希望末尾有3個，因此讓我們通過在輸入的匹配末尾之前添加額外的“ \ d”來明確聲明這一點：
"125465778".replace(/(\d)(?=(\d\d)+\d$)/g, "$1,");
-> "12,54,65,778"
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