我有一個PHP代碼，需要將數據庫表數據編碼為json。所以我使用了json_encode（）。我使用此處給出的表格-http: //www.geekality.net/2011/08/21/country-names-continent-names-and-iso-3166-codes-for-mysql/對于不同的輸入，此代碼的行為似乎有所不同。查詢- $query = "SELECT * FROM countries ";不返回任何json值。查詢- $query = "SELECT * FROM countries where continent_code='AS'";正確返回json值。但是，$query = "SELECT * FROM countries where continent_code='EU'";也不會返回任何內容。同樣，“ NA”，“ AF”無效，而其他人則完美。我對PHP的json_encode的這種行為感到奇怪。這是我的代碼。<?php$con=mysqli_connect('localhost','xxxx','xxxxx','joomla30');// Check connectionif (mysqli_connect_errno())  {  echo "Failed to connect to MySQL: " . mysqli_connect_error();  }$result = mysqli_query($con,"SELECT * FROM countries where continent_code='EU'") or die (mysqli_error($con));while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {      $orders[] = array(          'CountryCode' => $row['code'],          'CountryName' => $row['name']          );  }//print_r($orders);echo json_encode($orders);mysqli_close($con);?>直到json_encode的上一行為止，數據都會被攜帶。所以我認為它的json編碼問題。我嘗試使用來了解它print_r($orders);。我從中得到以下輸出。如果我嘗試使用“ EU”，則會得到該數組。Array ( [0] => Array ( [CountryCode] => AD [CountryName] => Andorra ) [1] => Array ( [CountryCode] => AL [CountryName] => Albania ) [2] => Array ( [CountryCode] => AT [CountryName] => Austria ) [3] => Array ( [CountryCode] => AX [CountryName] => ?land Islands )...如果我嘗試使用“ AS”，則會得到該數組。Array ( [0] => Array ( [CountryCode] => AE [CountryName] => United Arab Emirates ) [1] => Array ( [CountryCode] => AF [CountryName] => Afghanistan) [2] => Array ( [CountryCode] => AM [CountryName] => Armenia) [3] => Array ( [CountryCode] => AZ [CountryName] => Azerbaijan)...這兩個數組看起來都差不多……但是Json_encode僅在'AS'上有效，而在'EU'上無效。有誰知道如何解決這個問題？如果是這樣，請告訴我。