有沒有辦法讓我在java中獲取窗口的X和Y值？我讀到我將不得不使用運行時，因為java不能直接混亂，但是我不太清楚如何做到這一點。誰能指出一些如何獲得這個的鏈接/提示？
3 回答
繁星淼淼
TA貢獻1775條經驗 獲得超11個贊
要獲得“任何其他無關應用程序”的x和y位置，您將不得不查詢操作系統，這意味著可能使用JNI，JNA或其他一些腳本實用程序，如AutoIt（如果是Windows）。我建議使用JNA或腳本實用程序，因為它們比JNI（我的經驗有限）更容易使用，但要使用它們，您需要下載一些代碼并將其與Java應用程序集成。
編輯1 我不是JNA專家，但是我確實把它搞砸了，這就是我得到一些命名窗口的窗口坐標：
import java.util.Arrays;
import com.sun.jna.*;
import com.sun.jna.platform.win32.WinDef.HWND;
import com.sun.jna.win32.*;
public class GetWindowRect {
public interface User32 extends StdCallLibrary {
User32 INSTANCE = (User32) Native.loadLibrary("user32", User32.class,
W32APIOptions.DEFAULT_OPTIONS);
HWND FindWindow(String lpClassName, String lpWindowName);
int GetWindowRect(HWND handle, int[] rect);
}
public static int[] getRect(String windowName) throws WindowNotFoundException,
GetWindowRectException {
HWND hwnd = User32.INSTANCE.FindWindow(null, windowName);
if (hwnd == null) {
throw new WindowNotFoundException("", windowName);
}
int[] rect = {0, 0, 0, 0};
int result = User32.INSTANCE.GetWindowRect(hwnd, rect);
if (result == 0) {
throw new GetWindowRectException(windowName);
}
return rect;
}
@SuppressWarnings("serial")
public static class WindowNotFoundException extends Exception {
public WindowNotFoundException(String className, String windowName) {
super(String.format("Window null for className: %s; windowName: %s",
className, windowName));
}
}
@SuppressWarnings("serial")
public static class GetWindowRectException extends Exception {
public GetWindowRectException(String windowName) {
super("Window Rect not found for " + windowName);
}
}
public static void main(String[] args) {
String windowName = "Document - WordPad";
int[] rect;
try {
rect = GetWindowRect.getRect(windowName);
System.out.printf("The corner locations for the window \"%s\" are %s",
windowName, Arrays.toString(rect));
} catch (GetWindowRect.WindowNotFoundException e) {
e.printStackTrace();
} catch (GetWindowRect.GetWindowRectException e) {
e.printStackTrace();
}
}
}
當然，為了實現這一點，需要下載JNA庫并將其放在Java類路徑或IDE的構建路徑中。
12345678_0001
TA貢獻1802條經驗 獲得超5個贊
在最終用戶的幫助下，這很容易做到。讓他們點擊屏幕截圖中的一個點。
例如
import java.awt.*;
import java.awt.event.*;
import java.awt.image.*;
import javax.swing.*;
/** Getting a point of interest on the screen.
Requires the MotivatedEndUser API - sold separately. */
class GetScreenPoint {
public static void main(String[] args) throws Exception {
Robot robot = new Robot();
final Dimension screenSize = Toolkit.getDefaultToolkit().
getScreenSize();
final BufferedImage screen = robot.createScreenCapture(
new Rectangle(screenSize));
SwingUtilities.invokeLater(new Runnable() {
public void run() {
JLabel screenLabel = new JLabel(new ImageIcon(screen));
JScrollPane screenScroll = new JScrollPane(screenLabel);
screenScroll.setPreferredSize(new Dimension(
(int)(screenSize.getWidth()/2),
(int)(screenSize.getHeight()/2)));
final Point pointOfInterest = new Point();
JPanel panel = new JPanel(new BorderLayout());
panel.add(screenScroll, BorderLayout.CENTER);
final JLabel pointLabel = new JLabel(
"Click on any point in the screen shot!");
panel.add(pointLabel, BorderLayout.SOUTH);
screenLabel.addMouseListener(new MouseAdapter() {
public void mouseClicked(MouseEvent me) {
pointOfInterest.setLocation(me.getPoint());
pointLabel.setText(
"Point: " +
pointOfInterest.getX() +
"x" +
pointOfInterest.getY());
}
});
JOptionPane.showMessageDialog(null, panel);
System.out.println("Point of interest: " + pointOfInterest);
}
});
}
}
典型輸出
Point of interest: java.awt.Point[x=342,y=43]
Press any key to continue . . .
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