通過POST（ajax）發送JSON數據并從Controller（MVC）接收json響應我在javascript中創建了一個函數：function addNewManufacturer() {
var name = $("#id-manuf-name").val();
var address = $("#id-manuf-address").val();
var phone = $("#id-manuf-phone").val();
var sendInfo = {
Name: name,
Address: address,
Phone: phone };
$.ajax({
type: "POST",
url: "/Home/Add",
dataType: "json",
success: function (msg) {
if (msg) {
alert("Somebody" + name + " was added in list !");
location.reload(true);
} else {
alert("Cannot add to list !");
}
},
data: sendInfo });}我調用了jquery.json-2.3.min.js腳本文件，并將其用于toJSON(array)方法。在控制器中，我有這個Add動作[HttpPost]public ActionResult Add(PersonSheets sendInfo) {
bool success = _addSomethingInList.AddNewSomething( sendInfo );
return this.Json( new {
msg = success });}但是sendInfo當方法參數變為null時。該模型：public struct PersonSheets{
public int Id;
public string Name;
public string Address;
public string Phone;}public class PersonModel{
private List<PersonSheets> _list;
public PersonModel() {
_list= GetFakeData();
}
public bool AddNewSomething(PersonSheets info) {
if ( (info as object) == null ) {
throw new ArgumentException( "Person list cannot be empty", "info" );
}
PersonSheets item= new PersonSheets();
item.Id = GetMaximumIdValueFromList( _list) + 1;
item.Name = info.Name;
item.Address = info.Address;
item.Phone = info.Phone;
_list.Add(item);
return true;
}}當用POST發送數據時，我怎么能用action方法呢？我不知道怎么用。此外，可以通過JSON發回響應（到ajax）？謝謝
3 回答
浮云間
TA貢獻1829條經驗 獲得超4個贊
var SendInfo= { SendInfo: [... your elements ...]};
$.ajax({
type: 'post',
url: 'Your-URI',
data: JSON.stringify(SendInfo),
contentType: "application/json; charset=utf-8",
traditional: true,
success: function (data) {
...
}
});并在行動
public ActionResult AddDomain(IEnumerable<PersonSheets> SendInfo){...你可以像這樣綁定你的數組
var SendInfo = [];$(this).parents('table').find('input:checked').each(function () {
var domain = {
name: $("#id-manuf-name").val(),
address: $("#id-manuf-address").val(),
phone: $("#id-manuf-phone").val(),
}
SendInfo.push(domain);});希望這可以幫到你。
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