在asp.net mvc中使用jQuery ajax上傳文件我的視圖中有一個文件<form id="upload" enctype="multipart/form-data">
<input type="file" name="fileUpload" id="fileUpload" size="23" /></form>和ajax請求$.ajax({
url: '<%=Url.Action("JsonSave","Survey") %>',
dataType: 'json',
processData: false,
contentType: "multipart/mixed",
data: {
Id: selectedRow.Id,
Value: 'some date was added by the user here :))'
},
cache: false,
success: function (data) {}});但Request.Files中沒有文件。ajax請求有什么問題？
3 回答
qq_笑_17
TA貢獻1818條經驗 獲得超7個贊
現在可以通過將FormData對象傳遞給請求的data屬性來上傳AJAX文件$.ajax。
由于OP專門要求jQuery實現，所以你去：
<form?id="upload"?enctype="multipart/form-data"?action="@Url.Action("JsonSave",?"Survey")"?method="POST">
????<input?type="file"?name="fileUpload"?id="fileUpload"?size="23"?/><br?/>
????<button>Upload!</button></form>$('#upload').submit(function(e)?{
????e.preventDefault();?//?stop?the?standard?form?submission
????$.ajax({
????????url:?this.action,
????????type:?this.method,
????????data:?new?FormData(this),
????????cache:?false,
????????contentType:?false,
????????processData:?false,
????????success:?function?(data)?{
????????????console.log(data.UploadedFileCount?+?'?file(s)?uploaded?successfully');
????????},
????????error:?function(xhr,?error,?status)?{
????????????console.log(error,?status);
????????}
????});});public?JsonResult?Survey(){
????for?(int?i?=?0;?i?<?Request.Files.Count;?i++)
????{
????????var?file?=?Request.Files[i];
????????//?save?file?as?required?here...
????}
????return?Json(new?{?UploadedFileCount?=?Request.Files.Count?});}- 3 回答
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