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為了賬號安全,請及時綁定郵箱和手機立即綁定
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求大佬幫忙,老師今天講的太快,沒懂,作業不會做

求大佬幫忙,老師今天講的太快,沒懂,作業不會做

崔傭幸 2019-07-30 21:13:37
已知數據手機號數組:String[] phones = {"13804010040","13804010041","13804010042","13804010043","13804010044","13804010045","13804010046","13804010047","13804010044","13804010054","13804010055","13804010056","13804010058","13804010059","13804010060","13804010061","13804010062","13804010063","13804010064","13804010065","13804010066","13804010067","13804010068","13804010069","13804010070","13804010071","13804010072","13804010073","13804010074","13804010075","13804010045","13804010057","13804010063","13804010058","13804010069","13804010066"}1使用集合,快速去除重復的手機號,將去重后手機號存放的List集合中,輸出去重后有多少個手機號,13804010099這個手機號是否存在?2已知上面手機號數組,將數組轉為集合,然后使用map集合存儲每個手機號出現的次數,并遍歷輸出
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安浪創想

TA貢獻81條經驗 獲得超23個贊

做個遍歷,在遍歷的函數之外放一個全局變量。遍歷到了就改遍歷函數外的全局變量。這是學習算法的,還是要靠自己的邏輯去實現。

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