JavaJDBC-如何使用服務名稱而不是SID連接到Oracle我有一個使用JDBC(通過JPA)的Java應用程序,它使用主機名、端口和Oracle SID連接到開發數據庫,如下所示:jdbc:oracle:thin:@oracle.hostserver1.mydomain.ca:1521:XYZXYZ是Oracle SID。現在,我需要連接到一個不同的Oracle數據庫,它不使用SID,而是使用Oracle的“服務名稱”。我試過了,但沒用:jdbc:oracle:thin:@oracle.hostserver2.mydomain.ca:1522:ABCDABCD是另一個數據庫的服務名稱。我做錯什么了?
3 回答
明月笑刀無情
TA貢獻1828條經驗 獲得超4個贊
jdbc:oracle:thin:@//HOSTNAME:PORT/SERVICENAME
jdbc:oracle:thin:@(description=(address=(host=HOSTNAME)(protocol=tcp)(port=PORT))(connect_data=(service_name=SERVICENAME)(server=SHARED)))
瀟瀟雨雨
TA貢獻1833條經驗 獲得超4個贊
import java.sql.*; public class MyDBConnect {
public static void main(String[] args) throws SQLException {
try {
String dbURL = "jdbc:oracle:thin:@(DESCRIPTION=(ADDRESS_LIST=(ADDRESS=(PROTOCOL=TCP)(HOST=whatEverYourHostNameIs)(PORT=1521)))(CONNECT_DATA=(SERVICE_NAME=yourServiceName)))";
String strUserID = "yourUserId";
String strPassword = "yourPassword";
Connection myConnection=DriverManager.getConnection(dbURL,strUserID,strPassword);
Statement sqlStatement = myConnection.createStatement();
String readRecordSQL = "select * from sa_work_order where WORK_ORDER_NO = '1503090' ";
ResultSet myResultSet = sqlStatement.executeQuery(readRecordSQL);
while (myResultSet.next()) {
System.out.println("Record values: " + myResultSet.getString("WORK_ORDER_NO"));
}
myResultSet.close();
myConnection.close();
} catch (Exception e) {
System.out.println(e);
}
}}添加回答
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