如何防止java.lang.NumberFormatException：用于輸入字符串：“N/A”？在運行我的代碼時，我得到了一個NumberFormatException:java.lang.NumberFormatException: For input string: "N/A"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at java.lang.Integer.valueOf(Unknown Source)
at java.util.TreeMap.compare(Unknown Source)
at java.util.TreeMap.put(Unknown Source)
at java.util.TreeSet.add(Unknown Source)`如何防止此異常發生？
3 回答
寶慕林4294392
TA貢獻2021條經驗 獲得超8個贊
"N/A"NumberFormatException
Exception
異常處理*
try{
int i = Integer.parseInt(input);}catch(NumberFormatException ex){ // handle your exception
...}String input=...;String pattern ="-?\\d+";if(input.matches("-?\\d+")){ // any positive or negetive integer or not!
...}
忽然笑
TA貢獻1806條經驗 獲得超5個贊
N/AintNumberFormatException .
String str="N/A";
try {
int val=Integer.parseInt(str);
}catch (NumberFormatException e){
System.out.println("not a number");
}
皈依舞
TA貢獻1851條經驗 獲得超3個贊
private int ConvertIntoNumeric(String xVal){
try
{
return Integer.parseInt(xVal);
}
catch(Exception ex)
{
return 0;
}}....int xTest = ConvertIntoNumeric("N/A"); //Will return 0添加回答
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