3 回答

TA貢獻1829條經驗 獲得超4個贊
SELECT @row := @row + 1 as row, t.*FROM some_table t, (SELECT @row := 0) r
@row

TA貢獻1852條經驗 獲得超7個贊
以下內容將返回1.10000,并且不會太慢
SELECT @row := @row + 1 AS row FROM
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t2,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t3,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t4,
(SELECT @row:=0) numbers;
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