如何將JSON字符串轉換為字典？我想在我的快速項目中創建一個函數，將字符串轉換為Dicaryjson格式，但我有一個錯誤：無法轉換表達式的類型(@lvalue NSData，Options：IntegerLitralConverable)這是我的密碼：func convertStringToDictionary (text:String) -> Dictionary<String,String> {
var data :NSData = text.dataUsingEncoding(NSUTF8StringEncoding)!
var json :Dictionary = NSJSONSerialization.JSONObjectWithData(data, options:0, error: nil)
return json}我在目標C中提出了這一職能：- (NSDictionary*)convertStringToDictionary:(NSString*)string {
NSError* error;
//giving error as it takes dic, array,etc only. not custom object. NSData *data = [string dataUsingEncoding:NSUTF8StringEncoding];
id json = [NSJSONSerialization JSONObjectWithData:data options:0 error:&error];
return json;}
3 回答
搖曳的薔薇
TA貢獻1793條經驗 獲得超6個贊
SWIFT 3
func convertToDictionary(text: String) -> [String: Any]? {
if let data = text.data(using: .utf8) {
do {
return try JSONSerialization.jsonObject(with: data, options: []) as? [String: Any]
} catch {
print(error.localizedDescription)
}
}
return nil}let str = "{\"name\":\"James\"}"let dict = convertToDictionary(text: str)SWIFT 2
func convertStringToDictionary(text: String) -> [String:AnyObject]? {
if let data = text.dataUsingEncoding(NSUTF8StringEncoding) {
do {
return try NSJSONSerialization.JSONObjectWithData(data, options: []) as? [String:AnyObject]
} catch let error as NSError {
print(error)
}
}
return nil}let str = "{\"name\":\"James\"}"let result = convertStringToDictionary(str)原始SWIFT 1答案：
func convertStringToDictionary(text: String) -> [String:String]? {
if let data = text.dataUsingEncoding(NSUTF8StringEncoding) {
var error: NSError?
let json = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.allZeros, error: &error) as? [String:String]
if error != nil {
println(error)
}
return json }
return nil}let str = "{\"name\":\"James\"}"let result = convertStringToDictionary(str)
// ["name": "James"]if let name = result?["name"] {
// The `?` is here because our `convertStringToDictionary` function returns an Optional println(name) // "James"}NSJSONSerialization
let json = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.allZeros, error: &error) as? [String:AnyObject]
func convertStringToDictionary(text: String) -> [String:AnyObject]? { ... }
30秒到達戰場
TA貢獻1828條經驗 獲得超6個贊
func convertStringToDictionary(text: String) -> [String:AnyObject]? {
if let data = text.dataUsingEncoding(NSUTF8StringEncoding) {
do {
let json = try NSJSONSerialization.JSONObjectWithData(data, options: .MutableContainers) as? [String:AnyObject]
return json } catch {
print("Something went wrong")
}
}
return nil}
偶然的你
TA貢獻1841條經驗 獲得超3個贊
JSONSerializationjsonObject(with:options:). jsonObject(with:options:)
class func jsonObject(with data: Data, options opt: JSONSerialization.ReadingOptions = []) throws -> Any
從給定的JSON數據返回Foundation對象。
jsonObject(with:options:)try, try?try!Any
#1.使用拋出并返回非可選類型的方法。
import Foundationfunc convertToDictionary(from text: String) throws -> [String: String] {
guard let data = text.data(using: .utf8) else { return [:] }
let anyResult: Any = try JSONSerialization.jsonObject(with: data, options: [])
return anyResult as? [String: String] ?? [:]}let string1 = "{\"City\":\"Paris\"}"do {
let dictionary = try convertToDictionary(from: string1)
print(dictionary) // prints: ["City": "Paris"]} catch {
print(error)}let string2 = "{\"Quantity\":100}"do {
let dictionary = try convertToDictionary(from: string2)
print(dictionary) // prints [:]} catch {
print(error)}let string3 = "{\"Object\"}"do {
let dictionary = try convertToDictionary(from: string3)
print(dictionary)} catch {
print(error) // prints: Error Domain=NSCocoaErrorDomain Code=3840 "No value for key in object around character 9."
UserInfo={NSDebugDescription=No value for key in object around character 9.}}#2.使用拋出并返回可選類型的方法
import Foundationfunc convertToDictionary(from text: String) throws -> [String: String]? {
guard let data = text.data(using: .utf8) else { return [:] }
let anyResult: Any = try JSONSerialization.jsonObject(with: data, options: [])
return anyResult as? [String: String]}let string1 = "{\"City\":\"Paris\"}"do {
let dictionary = try convertToDictionary(from: string1)
print(String(describing: dictionary)) // prints: Optional(["City": "Paris"])} catch {
print(error)}let string2 = "{\"Quantity\":100}"do {
let dictionary = try convertToDictionary(from: string2)
print(String(describing: dictionary)) // prints nil} catch {
print(error)}let string3 = "{\"Object\"}"do {
let dictionary = try convertToDictionary(from: string3)
print(String(describing: dictionary))} catch {
print(error) // prints: Error Domain=NSCocoaErrorDomain Code=3840 "No value for key in object around character 9."
UserInfo={NSDebugDescription=No value for key in object around character 9.}}#3.使用不拋出并返回非可選類型的方法。
import Foundationfunc convertToDictionary(from text: String) -> [String: String] {
guard let data = text.data(using: .utf8) else { return [:] }
let anyResult: Any? = try? JSONSerialization.jsonObject(with: data, options: [])
return anyResult as? [String: String] ?? [:]}let string1 = "{\"City\":\"Paris\"}"let dictionary1 = convertToDictionary(from: string1)print(dictionary1) // prints: ["City": "Paris"]let string2 = "{\"Quantity\":100}"let dictionary2 = convertToDictionary(from: string2)print(dictionary2) // prints: [:]let string3 = "{\"Object\"}"let dictionary3 = convertToDictionary(from: string3)print(dictionary3) // prints: [:]#4.使用不拋出并返回可選類型的方法
import Foundationfunc convertToDictionary(from text: String) -> [String: String]? {
guard let data = text.data(using: .utf8) else { return nil }
let anyResult = try? JSONSerialization.jsonObject(with: data, options: [])
return anyResult as? [String: String]}let string1 = "{\"City\":\"Paris\"}"let dictionary1 = convertToDictionary(from: string1)print(String(describing: dictionary1))
// prints: Optional(["City": "Paris"])let string2 = "{\"Quantity\":100}"let dictionary2 = convertToDictionary(from: string2)print(String(describing: dictionary2))
// prints: nillet string3 = "{\"Object\"}"let dictionary3 = convertToDictionary(from: string3)print(String(describing: dictionary3))
// prints: nil- 3 回答
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