目標C中連接NSString的快捷方式有什么捷徑可以(stringByAppendingString:)目標-C中的字符串連接，或用于使用NSString總體而言?例如，我想做：NSString *myString = @"This";NSString *test = [myString stringByAppendingString:@" is just a test"];更像是：string myString = "This";string test = myString + " is just a test";
3 回答
牛魔王的故事
TA貢獻1830條經驗 獲得超3個贊
NSMutableStringappendString
NSArraycomponentsJoinedByString
墨色風雨
TA貢獻1853條經驗 獲得超6個贊
一種選擇：
[NSString stringWithFormat:@"%@/%@/%@", one, two, three];
另一種選擇：
NSLog(@"%@", [Util append:one, @" ", two, nil]); // "one two"NSLog(@"%@", [Util append:three, @"/", two, @"/", one, nil]); // three/two/one
+ (NSString *) append:(id) first, ...{
NSString * result = @"";
id eachArg;
va_list alist;
if(first)
{
result = [result stringByAppendingString:first];
va_start(alist, first);
while (eachArg = va_arg(alist, id))
result = [result stringByAppendingString:eachArg];
va_end(alist);
}
return result;}
慕的地6264312
TA貢獻1817條經驗 獲得超6個贊
NSString *joinedFromLiterals = @"ONE " @"MILLION " @"YEARS " @"DUNGEON!!!";
#define STRINGA @"Also, I don't know "#define STRINGB @"where food comes from."#define JOINED STRINGA STRINGB
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