如何在列表中找到數字的累積和？time_interval = [4, 6, 12]我想總結一下這些數字[4, 4+6, 4+6+12]為了得到名單t = [4, 10, 22].我嘗試了以下幾點：for i in time_interval:
t1 = time_interval[0]
t2 = time_interval[1] + t1
t3 = time_interval[2] + t2 print(t1, t2, t3)4 10 224 10 224 10 22
3 回答
婷婷同學_
TA貢獻1844條經驗 獲得超8個贊
numpycumsum:
import numpy as np a = [4,6,12]np.cumsum(a)#array([4, 10, 22])
accumu:
In [136]: timeit list(accumu(range(1000)))10000 loops, best of 3: 161 us per loopIn [137]: timeit list(accumu(xrange(1000)))10000 loops, best of 3: 147 us per loopIn [138]: timeit np.cumsum(np.arange(1000))100000 loops, best of 3: 10.1 us per loop
開心每一天1111
TA貢獻1836條經驗 獲得超13個贊
a = [4, 6, 12]reduce(lambda c, x: c + [c[-1] + x], a, [0])[1:]
[4, 10, 22]
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