如何在雙引號字符串中使用對象的屬性？我有以下代碼：$DatabaseSettings = @();$NewDatabaseSetting = "" | select DatabaseName, DataFile, LogFile, LiveBackupPath;$NewDatabaseSetting.
DatabaseName = "LiveEmployees_PD";$NewDatabaseSetting.DataFile = "LiveEmployees_PD_Data";$NewDatabaseSetting.LogFile = "LiveEmployees_PD_Log";
$NewDatabaseSetting.LiveBackupPath = '\\LiveServer\LiveEmployeesBackups';$DatabaseSettings += $NewDatabaseSetting;當我嘗試使用字符串執行命令中的一個屬性時：& "$SQlBackupExePath\SQLBackupC.exe" -I $InstanceName -SQL `
"RESTORE DATABASE $DatabaseSettings[0].DatabaseName FROM DISK = '$tempPath\$LatestFullBackupFile' WITH NORECOVERY, REPLACE,
MOVE '$DataFileName' TO '$DataFilegroupFolder\$DataFileName.mdf', MOVE '$LogFileName' TO '$LogFilegroupFolder\$LogFileName.ldf'"它只使用$DatabaseSettings而不是$DatabaseSettings[0].DatabaseName，這是無效的。我的解決辦法是將它復制到一個新變量中。如何以雙引號字符串直接訪問對象的屬性？
3 回答
慕后森
TA貢獻1802條經驗 獲得超5個贊
$foo = 2"$foo"
"2"
$foo = 2'$foo'
$():
$foo = 1,2,3"$foo[1]" # yields "1 2 3[1]""$($foo[1])" # yields "2"$bar = "abc""$bar.Length" # yields "abc.Length""$($bar.Length)" # yields "3"
$( )
慕姐4208626
TA貢獻1852條經驗 獲得超7個贊
$():
ToString()
...\$LogFileName.ldf
...\
$LogFileNameldf, $null
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