如何從python中的線程獲得返回值？功能foo下面返回一個字符串'foo'..我怎樣才能得到價值'foo'哪個是從線程的目標返回的？from threading import Threaddef foo(bar):
print('hello {}'.format(bar))
return 'foo'thread = Thread(target=foo, args=('world!',))thread.start()return_value = thread.join()上面所示的“一種顯而易見的方法”是行不通的：thread.join()退回來None.
3 回答
白豬掌柜的
TA貢獻1893條經驗 獲得超10個贊
def foo(bar, result, index):
print 'hello {0}'.format(bar)
result[index] = "foo"from threading import Threadthreads = [None] * 10results = [None] * 10for i in range(len(threads)):
threads[i] = Thread(target=foo, args=('world!', results, i))
threads[i].start()# do some other stufffor i in range(len(threads)):
threads[i].join()print " ".join(results) # what sound does a metasyntactic locomotive make?join()Thread
from threading import Threaddef foo(bar):
print 'hello {0}'.format(bar)
return "foo"class ThreadWithReturnValue(Thread):
def __init__(self, group=None, target=None, name=None,
args=(), kwargs={}, Verbose=None):
Thread.__init__(self, group, target, name, args, kwargs, Verbose)
self._return = None
def run(self):
if self._Thread__target is not None:
self._return = self._Thread__target(*self._Thread__args,
**self._Thread__kwargs)
def join(self):
Thread.join(self)
return self._return
twrv = ThreadWithReturnValue(target=foo, args=('world!',))twrv.start()print twrv.join() # prints fooThread
class ThreadWithReturnValue(Thread):
def __init__(self, group=None, target=None, name=None,
args=(), kwargs={}, Verbose=None):
Thread.__init__(self, group, target, name, args, kwargs)
self._return = None
def run(self):
print(type(self._target))
if self._target is not None:
self._return = self._target(*self._args,
**self._kwargs)
def join(self, *args):
Thread.join(self, *args)
return self._return添加回答
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