漂亮-用PHP打印JSON我正在構建一個將JSON數據提供給另一個腳本的PHP腳本。我的腳本將數據構建到一個大型關聯數組中，然后使用json_encode..下面是一個示例腳本：$data = array('a' => 'apple', 'b' => 'banana', 'c' => 'catnip');header('Content-type: text/javascript');echo json_encode($data);上面的代碼產生以下輸出：{"a":"apple","b":"banana","c":"catnip"}如果您有少量的數據，這是很好的，但是我更喜歡這樣的東西：{
"a": "apple",
"b": "banana",
"c": "catnip"}有什么方法可以在PHP中做到這一點而不受攻擊呢？好像有人在臉書弄明白了。
3 回答
躍然一笑
TA貢獻1826條經驗 獲得超6個贊
prettyPrint( $json ) === prettyPrint( prettyPrint( $json ) )
{"key1":[1,2,3],"key2":"value"}{
"key1": [
1,
2,
3
],
"key2": "value"}function prettyPrint( $json ){
$result = '';
$level = 0;
$in_quotes = false;
$in_escape = false;
$ends_line_level = NULL;
$json_length = strlen( $json );
for( $i = 0; $i < $json_length; $i++ ) {
$char = $json[$i];
$new_line_level = NULL;
$post = "";
if( $ends_line_level !== NULL ) {
$new_line_level = $ends_line_level;
$ends_line_level = NULL;
}
if ( $in_escape ) {
$in_escape = false;
} else if( $char === '"' ) {
$in_quotes = !$in_quotes;
} else if( ! $in_quotes ) {
switch( $char ) {
case '}': case ']':
$level--;
$ends_line_level = NULL;
$new_line_level = $level;
break;
case '{': case '[':
$level++;
case ',':
$ends_line_level = $level;
break;
case ':':
$post = " ";
break;
case " ": case "\t": case "\n": case "\r":
$char = "";
$ends_line_level = $new_line_level;
$new_line_level = NULL;
break;
}
} else if ( $char === '\\' ) {
$in_escape = true;
}
if( $new_line_level !== NULL ) {
$result .= "\n".str_repeat( "\t", $new_line_level );
}
$result .= $char.$post;
}
return $result;}
一只名叫tom的貓
TA貢獻1906條經驗 獲得超3個贊
echo json_encode($results, JSON_PRETTY_PRINT);
header('Content-Type: application/json');- 3 回答
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