快速提取正則匹配我想從匹配regex模式的字符串中提取子字符串。所以我在找這樣的東西：func matchesForRegexInText(regex: String!, text: String!) -> [String] {
???}所以這就是我所擁有的：func matchesForRegexInText(regex: String!, text: String!) -> [String] {
var regex = NSRegularExpression(pattern: regex,
options: nil, error: nil)
var results = regex.matchesInString(text,
options: nil, range: NSMakeRange(0, countElements(text)))
as Array<NSTextCheckingResult>
/// ???
return ...}問題是，matchesInString給我一個數組NSTextCheckingResult，在哪里NSTextCheckingResult.range是類型的NSRange.NSRange是不相容的Range<String.Index>，所以它阻止了我使用text.substringWithRange(...)知道如何在沒有太多代碼行的情況下快速實現這個簡單的事情嗎？
3 回答
慕少森
TA貢獻2019條經驗 獲得超9個贊
返回不僅匹配，而且 返回所有捕獲組
對于每一場比賽(見下面的例子) 而不是返回一個空數組，這個解決方案 支持可選匹配
避 do/catch通過不打印到控制臺和 使用 guard構造 加 matchingStrings作為 擴展到 String
SWIFT 4.2
//: Playground - noun: a place where people can playimport Foundationextension String {
func matchingStrings(regex: String) -> [[String]] {
guard let regex = try? NSRegularExpression(pattern: regex, options: []) else { return [] }
let nsString = self as NSString
let results = regex.matches(in: self, options: [], range: NSMakeRange(0, nsString.length))
return results.map { result in
(0..<result.numberOfRanges).map {
result.range(at: $0).location != NSNotFound
? nsString.substring(with: result.range(at: $0))
: ""
}
}
}}"prefix12 aaa3 prefix45".matchingStrings(regex: "fix([0-9])([0-9])")// Prints: [["fix12", "1", "2"], ["fix45", "4", "5"]]"prefix12"
.matchingStrings(regex: "(?:prefix)?([0-9]+)")// Prints: [["prefix12", "12"]]"12".matchingStrings(regex: "(?:prefix)?([0-9]+)")
// Prints: [["12", "12"]], other answers return an empty array here// Safely accessing the capture of the first match (if any):let
number = "prefix12suffix".matchingStrings(regex: "fix([0-9]+)su").first?[1]// Prints: Optional("12")SWIFT 3
//: Playground - noun: a place where people can playimport Foundationextension String {
func matchingStrings(regex: String) -> [[String]] {
guard let regex = try? NSRegularExpression(pattern: regex, options: []) else { return [] }
let nsString = self as NSString
let results = regex.matches(in: self, options: [], range: NSMakeRange(0, nsString.length))
return results.map { result in
(0..<result.numberOfRanges).map {
result.rangeAt($0).location != NSNotFound
? nsString.substring(with: result.rangeAt($0))
: ""
}
}
}}"prefix12 aaa3 prefix45".matchingStrings(regex: "fix([0-9])([0-9])")// Prints: [["fix12", "1", "2"], ["fix45", "4", "5"]]"prefix12".
matchingStrings(regex: "(?:prefix)?([0-9]+)")// Prints: [["prefix12", "12"]]"12".matchingStrings(regex: "(?:prefix)?([0-9]+)")
// Prints: [["12", "12"]], other answers return an empty array here// Safely accessing the capture of the first match (if any):let
number = "prefix12suffix".matchingStrings(regex: "fix([0-9]+)su").first?[1]// Prints: Optional("12")SWIFT 2
extension String {
func matchingStrings(regex: String) -> [[String]] {
guard let regex = try? NSRegularExpression(pattern: regex, options: []) else { return [] }
let nsString = self as NSString
let results = regex.matchesInString(self, options: [], range: NSMakeRange(0, nsString.length))
return results.map { result in
(0..<result.numberOfRanges).map {
result.rangeAtIndex($0).location != NSNotFound
? nsString.substringWithRange(result.rangeAtIndex($0))
: ""
}
}
}}- 3 回答
- 0 關注
- 726 瀏覽
添加回答
舉報
0/150
提交
取消