如何檢測iPhone 5(寬屏設備)？我剛剛升級到XCode4.5GM，并發現您現在可以將‘4“Retina大小應用于您的故事板視圖控制器?，F在，如果我想創建一個運行在iPhone 4和iPhone 5上的應用程序，當然，我必須構建每個窗口兩次，但我還必須檢測用戶是否有一個3.5“或4”屏幕的iPhone，然后應用該視圖。我該怎么做？
3 回答
白豬掌柜的
TA貢獻1893條經驗 獲得超10個贊
[ [ UIScreen mainScreen ] bounds ].size.height
#define IS_IPHONE_5 ( fabs( ( double )[ [ UIScreen mainScreen ] bounds ].size.height - ( double )568 ) < DBL_EPSILON )
fabs
if( IS_IPHONE_5 ){}else{}編輯-更好的檢測
IS_WIDESCREEN:
#define IS_WIDESCREEN ( fabs( ( double )[ [ UIScreen mainScreen ] bounds ].size.height - ( double )568 ) < DBL_EPSILON )
#define IS_IPHONE ( [ [ [ UIDevice currentDevice ] model ] isEqualToString: @"iPhone" ] )#define IS_IPOD ( [ [ [ UIDevice currentDevice ] model ] isEqualToString: @"iPod touch" ] )
IS_IPHONE_5
#define IS_IPHONE_5 ( IS_IPHONE && IS_WIDESCREEN )
重要-iOS 8支持
boundsUIScreen
nativeBoundsboundsnativeBounds
nativeBounds
if( [ [ UIScreen mainScreen ] respondsToSelector: @selector( nativeBounds ) ] ){
/* Detect using nativeBounds - iOS 8 and greater */}else{
/* Detect using bounds - iOS 7 and lower */}#define IS_WIDESCREEN_IOS7 ( fabs( ( double )[ [ UIScreen mainScreen ] bounds ].size.height - ( double )568 ) < DBL_EPSILON ) #define IS_WIDESCREEN_IOS8 ( fabs( ( double )[ [ UIScreen mainScreen ] nativeBounds ].size.height - ( double )1136 ) < DBL_EPSILON )#define IS_WIDESCREEN ( ( [ [ UIScreen mainScreen ] respondsToSelector: @selector( nativeBounds ) ] ) ? IS_WIDESCREEN_IOS8 : IS_WIDESCREEN_IOS7 )
SMILET
TA貢獻1796條經驗 獲得超4個贊
if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone){
CGSize result = [[UIScreen mainScreen] bounds].size;
if(result.height == 480)
{
// iPhone Classic
}
if(result.height == 568)
{
// iPhone 5
}}- 3 回答
- 0 關注
- 523 瀏覽
添加回答
舉報
0/150
提交
取消