TA貢獻1810條經驗 獲得超5個贊
正則表達式以獲取Javascript中兩個字符串之間的字符串
.[^][\s\S]/[\d\D]/[\w\W]
s.
var result = s.match(/(?<=cow\s+).*?(?=\s+milk)/gs); // Returns multiple matches if any// Orvar result = s.match(/(?<=cow\s*). *?(?=\s*milk)/gs); // Same but whitespaces are optional
cowcowmilk
所有JS環境都支持此方案和以下所有其他方案。參見答案底部的用法示例。
cow (.*?) milk
cow*?milk
cow ([\s\S]*?) milk
cowmilk
>>>15 text>>>67 text2>>>>>>+number+whitespace>>>/>>>\d+\s(.*?)>>>/g>>>67
/>>>\d+\s(.*?)(?=>>>)/g
text1text2
.*?cowmilk"Their\ncow\ngives\nmore\nmilk"milkcow\n([\s\S]*?)\nmilk
/cow\n(.*(?:\n(?!milk$).*)*)\nmilk/gm
\r\n/cow\r?\n(.*(?:\r?\n(?!milk$).*)*)\r?\nmilk/gm
JavaScript中的示例regex用法：
//Single/First match expected: use no global modifier and access match[1]
console.log("My cow always gives milk".match(/cow (.*?) milk/)[1]);
// Multiple matches: get multiple matches with a global modifier and
// trim the results if length of leading/trailing delimiters is known
var s = "My cow always gives milk, thier cow also gives milk";
console.log(s.match(/cow (.*?) milk/g).map(function(x) {return x.substr(4,x.length-9);}));
//or use RegExp#exec inside a loop to collect all the Group 1 contents
var result = [], m, rx = /cow (.*?) milk/g;
while ((m=rx.exec(s)) !== null) {
result.push(m[1]);
}
console.log(result);
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