如何強制NSLocalizedString使用特定語言在iPhone上NSLocalizedString返回iPhone語言中的字符串。有沒有可能強迫NSLocalizedString使用一種特定的語言使應用程序使用與設備不同的語言？
4 回答
慕婉清6462132
TA貢獻1804條經驗 獲得超2個贊
請勿在iOS 9上使用。這將對通過它傳遞的所有字符串返回零。
我找到了另一個解決方案，允許您更新語言字符串，w/o重新啟動應用程序，并與genstring兼容：
將這個宏放在前綴中.pch：
#define currentLanguageBundle [NSBundle bundleWithPath:[[NSBundle mainBundle] pathForResource:[[NSLocale preferredLanguages] objectAtIndex:0] ofType:@"lproj"]]
在任何需要本地化字符串的地方：
NSLocalizedStringFromTableInBundle(@"GalleryTitleKey", nil, currentLanguageBundle, @"")
設置語言使用：
[[NSUserDefaults standardUserDefaults] setObject:[NSArray arrayWithObject:@"de"] forKey:@"AppleLanguages"];
即使在連續的語言跳躍中也能工作，例如：
NSLog(@"test %@", NSLocalizedStringFromTableInBundle(@"NewKey", nil, currentLanguageBundle, @""));
[[NSUserDefaults standardUserDefaults] setObject:[NSArray arrayWithObject:@"fr"] forKey:@"AppleLanguages"];
NSLog(@"test %@", NSLocalizedStringFromTableInBundle(@"NewKey", nil, currentLanguageBundle, @""));
[[NSUserDefaults standardUserDefaults] setObject:[NSArray arrayWithObject:@"it"] forKey:@"AppleLanguages"];
NSLog(@"test %@", NSLocalizedStringFromTableInBundle(@"NewKey", nil, currentLanguageBundle, @""));
[[NSUserDefaults standardUserDefaults] setObject:[NSArray arrayWithObject:@"de"] forKey:@"AppleLanguages"];
NSLog(@"test %@", NSLocalizedStringFromTableInBundle(@"NewKey", nil, currentLanguageBundle, @""));
富國滬深
TA貢獻1790條經驗 獲得超9個贊
NSLocalizedString()NSUserDefaults
[[NSUserDefaults standardUserDefaults] setObject:[NSArray arrayWithObjects:@"de", @"en", @"fr", nil] forKey:@"AppleLanguages"]; [[NSUserDefaults standardUserDefaults] synchronize]; //to make the change immediate
波斯汪
TA貢獻1811條經驗 獲得超4個贊
頭文件
@interface NSBundle (Language)+(void)setLanguage:(NSString*)language;@end
實施
#import <objc/runtime.h>static const char _bundle=0;@interface BundleEx :
NSBundle@end@implementation BundleEx-(NSString*)localizedStringForKey:(NSString *)key value:(NSString *)value table:(NSString *)tableName{
NSBundle* bundle=objc_getAssociatedObject(self, &_bundle);
return bundle ? [bundle localizedStringForKey:key value:value table:tableName] : [super localizedStringForKey:
key value:value table:tableName];}@end@implementation NSBundle (Language)+(void)setLanguage:(NSString*)language{
static dispatch_once_t onceToken;
dispatch_once(&onceToken, ^
{
object_setClass([NSBundle mainBundle],[BundleEx class]);
});
objc_setAssociatedObject([NSBundle mainBundle], &_bundle, language ? [NSBundle bundleWithPath:[[NSBundle mainBundle]
pathForResource:language ofType:@"lproj"]] : nil, OBJC_ASSOCIATION_RETAIN_NONATOMIC);}@end[NSBundle setLanguage:@"en"];
[NSBundle setLanguage:@"fr"];
[NSBundle setLanguage:nil];
var bundleKey: UInt8 = 0class AnyLanguageBundle: Bundle {
override func localizedString(forKey key: String,
value: String?,
table tableName: String?) -> String {
guard let path = objc_getAssociatedObject(self, &bundleKey) as? String,
let bundle = Bundle(path: path) else {
return super.localizedString(forKey: key, value: value, table: tableName)
}
return bundle.localizedString(forKey: key, value: value, table: tableName)
}}extension Bundle {
class func setLanguage(_ language: String) {
defer {
object_setClass(Bundle.main, AnyLanguageBundle.self)
}
objc_setAssociatedObject(Bundle.main, &bundleKey, Bundle.main.path(forResource: language, ofType: "lproj"),
.OBJC_ASSOCIATION_RETAIN_NONATOMIC)
}}
慕尼黑的夜晚無繁華
TA貢獻1864條經驗 獲得超6個贊
@implementation Languagestatic NSBundle *bundle = nil;+(void)initialize
{
NSUserDefaults* defs = [NSUserDefaults standardUserDefaults];
NSArray* languages = [defs objectForKey:@"AppleLanguages"];
NSString *current = [[languages objectAtIndex:0] retain];
[self setLanguage:current];}/*
example calls:
[Language setLanguage:@"it"];
[Language setLanguage:@"de"];
*/+(void)setLanguage:(NSString *)l{
NSLog(@"preferredLang: %@", l);
NSString *path = [[ NSBundle mainBundle ] pathForResource:l ofType:@"lproj" ];
bundle = [[NSBundle bundleWithPath:path] retain];}+(NSString *)get:(NSString *)key alter:(NSString *)alternate
{
return [bundle localizedStringForKey:key value:alternate table:nil];}@end- 4 回答
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