在Java中使用Double保持精度public class doublePrecision {
public static void main(String[] args) {
double total = 0;
total += 5.6;
total += 5.8;
System.out.println(total);
}}以上代碼打?。?1.399999999999我如何才能把它打印出來(或者可以用作)11.4？
3 回答
守著一只汪
TA貢獻1872條經驗 獲得超4個贊
33.33333333333333
33.3333333333333285963817615993320941925048828125
0.333333333333333285963817615993320941925048828125
0.3333333333333332593184650249895639717578887939453125
0.33333333333333326
拉風的咖菲貓
TA貢獻1995條經驗 獲得超2個贊
public class Fraction {private int numerator;private int denominator;public Fraction(int n, int d){
numerator = n;
denominator = d;}public double toDouble(){
return ((double)numerator)/((double)denominator);}public static Fraction add(Fraction a, Fraction b){
if(a.denominator != b.denominator){
double aTop = b.denominator * a.numerator;
double bTop = a.denominator * b.numerator;
return new Fraction(aTop + bTop, a.denominator * b.denominator);
}
else{
return new Fraction(a.numerator + b.numerator, a.denominator);
}}public static Fraction divide(Fraction a, Fraction b){
return new Fraction(a.numerator * b.denominator, a.denominator * b.numerator);}public static Fraction multiply(Fraction a, Fraction b){
return new Fraction(a.numerator * b.numerator, a.denominator * b.denominator);}public static Fraction subtract(Fraction a, Fraction b){
if(a.denominator != b.denominator){
double aTop = b.denominator * a.numerator;
double bTop = a.denominator * b.numerator;
return new Fraction(aTop-bTop, a.denominator*b.denominator);
}
else{
return new Fraction(a.numerator - b.numerator, a.denominator);
}}}添加回答
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