TA貢獻1818條經驗 獲得超8個贊
我假設你正在比較一個普通的數組。如果沒有，則需要將for循環更改為for ... in循環。
function arr_diff (a1, a2) {
var a = [], diff = [];
for (var i = 0; i < a1.length; i++) {
a[a1[i]] = true;
}
for (var i = 0; i < a2.length; i++) {
if (a[a2[i]]) {
delete a[a2[i]];
} else {
a[a2[i]] = true;
}
}
for (var k in a) {
diff.push(k);
}
return diff;
}
console.log(arr_diff(['a', 'b'], ['a', 'b', 'c', 'd']));
console.log(arr_diff("abcd", "abcde"));
console.log(arr_diff("zxc", "zxc"));
如果您不關心向后兼容性，更好的解決方案是使用過濾器。但是，這個解決方案仍然有效。
TA貢獻1712條經驗 獲得超3個贊
Array.prototype.diff = function(a) {
return this.filter(function(i) {return a.indexOf(i) < 0;});
};
////////////////////
// Examples
////////////////////
[1,2,3,4,5,6].diff( [3,4,5] );
// => [1, 2, 6]
["test1", "test2","test3","test4","test5","test6"].diff(["test1","test2","test3","test4"]);
// => ["test5", "test6"]
Array.prototype.diff = function(a) {
return this.filter(function(i) {return a.indexOf(i) < 0;});
};
////////////////////
// Examples
////////////////////
var dif1 = [1,2,3,4,5,6].diff( [3,4,5] );
console.log(dif1); // => [1, 2, 6]
var dif2 = ["test1", "test2","test3","test4","test5","test6"].diff(["test1","test2","test3","test4"]);
console.log(dif2); // => ["test5", "test6"]
注意 indexOf和filter在ie9之前不可用。
TA貢獻1802條經驗 獲得超5個贊
到目前為止，這是使用jQuery獲得您正在尋找的結果的最簡單方法：
var diff = $(old_array).not(new_array).get();
diff現在包含了old_array不存在的內容new_array
舉報