原數據：vardata=[{"name":"小明","age":"4","birthday":"5-1"},{"name":"小黃","age":"4","birthday":"5-1"},{"name":"小紅","age":"4","birthday":"5-3"},]希望整理后得到：varnewArr=[{"birthday":"5-1","detailList":"[{'name':'小明','age':'4'},{'name':'小黃','age':'4'}]"},{"birthday":"5-3","detailList":"[{'name':'小紅','age':'4'}]"}];我的思路；data數組第0項直接push（birthday+detailList）整個到新數組newArr，但從第1項就要開始去newArr比較birthday，如果birthday相同，就只用push（detailList），如果不同就push{birthday+detailList}遇到問題：重復打印了一些數據我的代碼：`vardata=[{"name":"小明","age":"4","birthday":"5-1"},{"name":"小黃","age":"4","birthday":"5-1"},{"name":"小紅","age":"4","birthday":"5-3"},]//[希望得到]//varnewArr=[//{//"birthday":"5-1",//"detailList":"[{'name':'小明','age':'4'},{'name':'小黃','age':'4'}]"http://},//{//"birthday":"5-3",//"detailList":"[{'name':'小紅','age':'4'}]"http://}//];vararr=[];//存放新數組for(vari=0;i
js 根據日期 對數組重新分組
慕勒3428872
2019-05-20 10:22:57
