function minzhi()local days={"1","2","3","4","5","6","7","8","9","0","a","b","c","d","e","f","g","h","j","k","l","q","w","e","r","t","y","u","i","o","p","z","x","c","v","b","n","m"}endprint (minzhi())如何讓函數每次運行，從第一個數組開起輸出，一直到最后一個，又從第一個輸出，這樣循環顯示
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largeQ
TA貢獻2039條經驗 獲得超8個贊
用 closure 最簡單，比如下面的代碼，每次調用 minzhi() 都會打印 days 里的元素。
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 | function newMinzhi() local days={"1","2","3","4","5","6","7","8","9","0","a","b","c","d","e","f","g","h","j","k","l","q","w", "e","r","t","y","u","i","o","p","z","x","c","v","b","n","m"} local idx = 1 return function () if idx > #days then idx = 1 end print(days[idx]) idx = idx + 1 end end
minzhi = newMinzhi() minzhi() -- 打印 1 minzhi() -- 打印 2 minzhi() -- 打印 3 ................ |
九州編程
TA貢獻1785條經驗 獲得超4個贊
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 | -- 之前的版本直接把內容打印出來了，現在的版本改成返回 days 中的值。
function newMinzhi() local days= {"中", "國"} local idx = 1 return function () if idx > #days then idx = 1 end local ret = days[idx] idx = idx + 1 return ret end end minzhi = newMinzhi() print(minzhi()) print(minzhi()) |
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