【PHP】laravel怎么獲取網址里面的參數
2 回答
明月笑刀無情
TA貢獻1828條經驗 獲得超4個贊
獲取網址參數直接get就行了啊
$view = array();
$view_list = array();
$view[source] = $_GET['utm_source'];
$view[medium] = $_GET['utm_medium'];
$view[campaign] = $_GET['utm_campaign'];
$view[content] = $_GET['utm_content'];
$time = time();
$view_list[$time] = $view;
動漫人物
TA貢獻1815條經驗 獲得超10個贊
| 123456789101112131415161718192021222324252627282930313233343536373839404142434445 | <?php$found = false;$view = array();$view_list = isset($_SESSION['view_list'])?$_SESSION['view_list']:array();$view["utm_source"] = $_GET['utm_source'];$view["utm_medium"] = $_GET['utm_medium'];$view["utm_campaign"] = $_GET['utm_campaign'];$view["utm_content"] = $_GET['utm_content'];$time = date("Y-m-d H:i:s",time());foreach($view_list as $row){ if( $row["utm_source"]==$view["utm_source"] && $row["utm_medium"]==$view["utm_medium"] && $row["utm_campaign"]==$view["utm_campaign"] && $row["utm_content"]==$view["utm_content"] &&){ //檢測重復 $found = true; break; }}if(!$found){ $view_list[$time] = $view; $_SESSION['view_list'] = $view_list; $_SESSION['last_view'] = $view;} //以上是保存訪問歷史部分?> <?php//下面是在提交時將數據保存到數據庫的部分$view_list = json_encode($_SESSION['view_list']);//將總數組編碼后的字符串$view_last = json_encode($_SESSION['last_view']);//將最后一次訪問編碼成字符串 //以上兩個數據存入數據庫即可 ?> <?php//從數據庫獲取數據//從數據庫取到數據后進行一次json解碼就可以拿到原來的數組了如下://$view_list_str $last_view_str分別是從數據庫中讀出來的字符串$view_list_array = json_encode($view_list_str);$view_last_array = json_encode($last_view_str); ?> |
- 2 回答
- 0 關注
- 1387 瀏覽
添加回答
舉報
0/150
提交
取消