web.xml中沒看出異常??？
比如輸入http://localhost:8080/dyn2/dy...會自動調整到http://localhost:8080/dyn2/login
<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<description>Dynamic Matrix powered by Spring</description>
<display-name>Dynamic Matrix</display-name>
<context-param>
<param-name>webAppRootKey</param-name>
<param-value>dyn2.root</param-value>
</context-param>
<context-param>
<param-name>log4jConfigLocation</param-name>
<param-value>/WEB-INF/log4j.properties</param-value>
</context-param>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<filter>
<filter-name>characterEncodingFilter</filter-name>
<filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
<init-param>
<param-name>encoding</param-name>
<param-value>utf8</param-value>
</init-param>
</filter>
<!--<filter>
<filter-name>ContentTypeFilter</filter-name>
<filter-class>net.counters.dynm.web.ContentTypeFilter</filter-class>
<init-param>
<param-name>charset</param-name>
<param-value>utf8</param-value>
</init-param>
</filter>
-->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<!-- <filter>
<filter-name>UrlRewriteFilter</filter-name>
<filter-class>org.tuckey.web.filters.urlrewrite.UrlRewriteFilter</filter-class>
</filter> -->
<filter-mapping>
<filter-name>characterEncodingFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<!--<filter-mapping>
<filter-name>ContentTypeFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
-->
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<!-- <filter-mapping>
<filter-name>UrlRewriteFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping> -->
<listener>
<listener-class>org.springframework.web.util.Log4jConfigListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.util.HttpSessionMutexListener</listener-class>
</listener>
<servlet>
<servlet-name>dynMatrix</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<!-- <servlet-mapping>
<servlet-name>dynMatrix</servlet-name>
<url-pattern>/app/*</url-pattern>
</servlet-mapping> -->
<servlet-mapping>
<servlet-name>dynMatrix</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>60</session-timeout>
</session-config>
<error-page>
<error-code>403</error-code>
<location>/errors/403.html</location>
</error-page>
</web-app>
這是controller
@RequestMapping(value="/create",method=RequestMethod.GET)
public String getCreateForm(Model model){
this.addEnableMap(model);
model.addAttribute(new WebUser());
//加載分類
String cwhere = " where type_parent_id=0";
List<CheckListType> checkListType = checkLMDao.getCheckListTypeByWhere(cwhere, 0, 0);
model.addAttribute("checkListType", checkListType);
return "createUserForm";
}
1 回答
交互式愛情
TA貢獻1712條經驗 獲得超3個贊
請求這條地址可能需要一些登錄信息什么的做驗證，在ajax里請求會把這些信息傳過去，
你直接瀏覽器輸入不帶有這些信息就會被security過濾器給攔截轉發到登錄頁面了。
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