亚洲在线久爱草,狠狠天天香蕉网,天天搞日日干久草,伊人亚洲日本欧美

為了賬號安全，請及時綁定郵箱和手機立即綁定
已解決430363個問題，去搜搜看，總會有你想問的

關于sql server中的表函數?

關于sql server中的表函數?

嗶嗶one 2018-12-13 19:11:59
關于sql server中的表函數
查看完整描述

1 回答

?
慕神8447489

TA貢獻1780條經驗 獲得超1個贊

這個問題用標致函數比較難，1樓調用標致函數的方法也是錯誤的，正確的方法應該是：
SELECT * FROM DBO.CaculateDailyTM（）

我用游標實現 ，比較好理解：

create table tb1(zm char(8),sd datetime,ed datetime)
GO
insert into tb1 values('s1','1980-1-1','1980-2-1')
insert into tb1 values('s2','1992-2-1','1993-3-1')
GO
--建立測試數據

declare zm_cursor cursor fast_forward for select zm from tb1
declare @t1 datetime,@t2 datetime,@zm char(8)
declare @tb table(zm char(8),d datetime)
open zm_cursor
fetch next from zm_cursor into @zm
while @@fetch_status=0
begin
select @t1=sd,@t2=ed from tb1 where zm=@zm
while @t1<=@t2
begin
insert into @tb values(@zm,@t1)
set @t1=dateadd(day,1,@t1)
end
fetch next from zm_cursor into @zm
end
select * from @tb
close zm_cursor
deallocate zm_cursor

GO

DROP TABLE TB1

有問題HI我

這個問題用標致函數比較難，1樓調用標致函數的方法也是錯誤的，正確的方法應該是：
SELECT * FROM DBO.CaculateDailyTM（）

我用游標實現 ，比較好理解：

create table tb1(zm char(8),sd datetime,ed datetime)
GO
insert into tb1 values('s1','1980-1-1','1980-2-1')
insert into tb1 values('s2','1992-2-1','1993-3-1')
GO
--建立測試數據

declare zm_cursor cursor fast_forward for select zm from tb1
declare @t1 datetime,@t2 datetime,@zm char(8)
declare @tb table(zm char(8),d datetime)
open zm_cursor
fetch next from zm_cursor into @zm
while @@fetch_status=0
begin
select @t1=sd,@t2=ed from tb1 where zm=@zm
while @t1<=@t2
begin
insert into @tb values(@zm,@t1)
set @t1=dateadd(day,1,@t1)
end
fetch next from zm_cursor into @zm
end
select * from @tb
close zm_cursor
deallocate zm_cursor

GO

DROP TABLE TB1

有問題HI我

這個問題用標致函數比較難，1樓調用標致函數的方法也是錯誤的，正確的方法應該是：
SELECT * FROM DBO.CaculateDailyTM（）

我用游標實現 ，比較好理解：

create table tb1(zm char(8),sd datetime,ed datetime)
GO
insert into tb1 values('s1','1980-1-1','1980-2-1')
insert into tb1 values('s2','1992-2-1','1993-3-1')
GO
--建立測試數據

declare zm_cursor cursor fast_forward for select zm from tb1
declare @t1 datetime,@t2 datetime,@zm char(8)
declare @tb table(zm char(8),d datetime)
open zm_cursor
fetch next from zm_cursor into @zm
while @@fetch_status=0
begin
select @t1=sd,@t2=ed from tb1 where zm=@zm
while @t1<=@t2
begin
insert into @tb values(@zm,@t1)
set @t1=dateadd(day,1,@t1)
end
fetch next from zm_cursor into @zm
end
select * from @tb
close zm_cursor
deallocate zm_cursor

GO

DROP TABLE TB1

有問題HI我

這個問題用標致函數比較難，1樓調用標致函數的方法也是錯誤的，正確的方法應該是：
SELECT * FROM DBO.CaculateDailyTM（）

我用游標實現 ，比較好理解：

create table tb1(zm char(8),sd datetime,ed datetime)
GO
insert into tb1 values('s1','1980-1-1','1980-2-1')
insert into tb1 values('s2','1992-2-1','1993-3-1')
GO
--建立測試數據

declare zm_cursor cursor fast_forward for select zm from tb1
declare @t1 datetime,@t2 datetime,@zm char(8)
declare @tb table(zm char(8),d datetime)
open zm_cursor
fetch next from zm_cursor into @zm
while @@fetch_status=0
begin
select @t1=sd,@t2=ed from tb1 where zm=@zm
while @t1<=@t2
begin
insert into @tb values(@zm,@t1)
set @t1=dateadd(day,1,@t1)
end
fetch next from zm_cursor into @zm
end
select * from @tb
close zm_cursor
deallocate zm_cursor

GO

DROP TABLE TB1

有問題HI我

這個問題用標致函數比較難，1樓調用標致函數的方法也是錯誤的，正確的方法應該是：
SELECT * FROM DBO.CaculateDailyTM（）

我用游標實現 ，比較好理解：

create table tb1(zm char(8),sd datetime,ed datetime)
GO
insert into tb1 values('s1','1980-1-1','1980-2-1')
insert into tb1 values('s2','1992-2-1','1993-3-1')
GO
--建立測試數據

declare zm_cursor cursor fast_forward for select zm from tb1
declare @t1 datetime,@t2 datetime,@zm char(8)
declare @tb table(zm char(8),d datetime)
open zm_cursor
fetch next from zm_cursor into @zm
while @@fetch_status=0
begin
select @t1=sd,@t2=ed from tb1 where zm=@zm
while @t1<=@t2
begin
insert into @tb values(@zm,@t1)
set @t1=dateadd(day,1,@t1)
end
fetch next from zm_cursor into @zm
end
select * from @tb
close zm_cursor
deallocate zm_cursor

GO

DROP TABLE TB1

有問題HI我

這個問題用標致函數比較難，1樓調用標致函數的方法也是錯誤的，正確的方法應該是：
SELECT * FROM DBO.CaculateDailyTM（）

我用游標實現 ，比較好理解：

create table tb1(zm char(8),sd datetime,ed datetime)
GO
insert into tb1 values('s1','1980-1-1','1980-2-1')
insert into tb1 values('s2','1992-2-1','1993-3-1')
GO
--建立測試數據

declare zm_cursor cursor fast_forward for select zm from tb1
declare @t1 datetime,@t2 datetime,@zm char(8)
declare @tb table(zm char(8),d datetime)
open zm_cursor
fetch next from zm_cursor into @zm
while @@fetch_status=0
begin
select @t1=sd,@t2=ed from tb1 where zm=@zm
while @t1<=@t2
begin
insert into @tb values(@zm,@t1)
set @t1=dateadd(day,1,@t1)
end
fetch next from zm_cursor into @zm
end
select * from @tb
close zm_cursor
deallocate zm_cursor

GO

DROP TABLE TB1

有問題HI我

這個問題用標致函數比較難，1樓調用標致函數的方法也是錯誤的，正確的方法應該是：
SELECT * FROM DBO.CaculateDailyTM（）

我用游標實現 ，比較好理解：

create table tb1(zm char(8),sd datetime,ed datetime)
GO
insert into tb1 values('s1','1980-1-1','1980-2-1')
insert into tb1 values('s2','1992-2-1','1993-3-1')
GO
--建立測試數據

declare zm_cursor cursor fast_forward for select zm from tb1
declare @t1 datetime,@t2 datetime,@zm char(8)
declare @tb table(zm char(8),d datetime)
open zm_cursor
fetch next from zm_cursor into @zm
while @@fetch_status=0
begin
select @t1=sd,@t2=ed from tb1 where zm=@zm
while @t1<=@t2
begin
insert into @tb values(@zm,@t1)
set @t1=dateadd(day,1,@t1)
end
fetch next from zm_cursor into @zm
end
select * from @tb
close zm_cursor
deallocate zm_cursor

GO

DROP TABLE TB1

有問題HI我

這個問題用標致函數比較難，1樓調用標致函數的方法也是錯誤的，正確的方法應該是：
SELECT * FROM DBO.CaculateDailyTM（）

我用游標實現 ，比較好理解：

create table tb1(zm char(8),sd datetime,ed datetime)
GO
insert into tb1 values('s1','1980-1-1','1980-2-1')
insert into tb1 values('s2','1992-2-1','1993-3-1')
GO
--建立測試數據

declare zm_cursor cursor fast_forward for select zm from tb1
declare @t1 datetime,@t2 datetime,@zm char(8)
declare @tb table(zm char(8),d datetime)
open zm_cursor
fetch next from zm_cursor into @zm
while @@fetch_status=0
begin
select @t1=sd,@t2=ed from tb1 where zm=@zm
while @t1<=@t2
begin
insert into @tb values(@zm,@t1)
set @t1=dateadd(day,1,@t1)
end
fetch next from zm_cursor into @zm
end
select * from @tb
close zm_cursor
deallocate zm_cursor

GO

DROP TABLE TB1

有問題HI我

這個問題用標致函數比較難，1樓調用標致函數的方法也是錯誤的，正確的方法應該是：
SELECT * FROM DBO.CaculateDailyTM（）

我用游標實現 ，比較好理解：

create table tb1(zm char(8),sd datetime,ed datetime)
GO
insert into tb1 values('s1','1980-1-1','1980-2-1')
insert into tb1 values('s2','1992-2-1','1993-3-1')
GO
--建立測試數據

declare zm_cursor cursor fast_forward for select zm from tb1
declare @t1 datetime,@t2 datetime,@zm char(8)
declare @tb table(zm char(8),d datetime)
open zm_cursor
fetch next from zm_cursor into @zm
while @@fetch_status=0
begin
select @t1=sd,@t2=ed from tb1 where zm=@zm
while @t1<=@t2
begin
insert into @tb values(@zm,@t1)
set @t1=dateadd(day,1,@t1)
end
fetch next from zm_cursor into @zm
end
select * from @tb
close zm_cursor
deallocate zm_cursor

GO

DROP TABLE TB1

有問題HI我

這個問題用標致函數比較難，1樓調用標致函數的方法也是錯誤的，正確的方法應該是：
SELECT * FROM DBO.CaculateDailyTM（）

我用游標實現 ，比較好理解：

create table tb1(zm char(8),sd datetime,ed datetime)
GO
insert into tb1 values('s1','1980-1-1','1980-2-1')
insert into tb1 values('s2','1992-2-1','1993-3-1')
GO
--建立測試數據

declare zm_cursor cursor fast_forward for select zm from tb1
declare @t1 datetime,@t2 datetime,@zm char(8)
declare @tb table(zm char(8),d datetime)
open zm_cursor
fetch next from zm_cursor into @zm
while @@fetch_status=0
begin
select @t1=sd,@t2=ed from tb1 where zm=@zm
while @t1<=@t2
begin
insert into @tb values(@zm,@t1)
set @t1=dateadd(day,1,@t1)
end
fetch next from zm_cursor into @zm
end
select * from @tb
close zm_cursor
deallocate zm_cursor

GO

DROP TABLE TB1

有問題HI我

這個問題用標致函數比較難，1樓調用標致函數的方法也是錯誤的，正確的方法應該是：
SELECT * FROM DBO.CaculateDailyTM（）

我用游標實現 ，比較好理解：

create table tb1(zm char(8),sd datetime,ed datetime)
GO
insert into tb1 values('s1','1980-1-1','1980-2-1')
insert into tb1 values('s2','1992-2-1','1993-3-1')
GO
--建立測試數據

declare zm_cursor cursor fast_forward for select zm from tb1
declare @t1 datetime,@t2 datetime,@zm char(8)
declare @tb table(zm char(8),d datetime)
open zm_cursor
fetch next from zm_cursor into @zm
while @@fetch_status=0
begin
select @t1=sd,@t2=ed from tb1 where zm=@zm
while @t1<=@t2
begin
insert into @tb values(@zm,@t1)
set @t1=dateadd(day,1,@t1)
end
fetch next from zm_cursor into @zm
end
select * from @tb
close zm_cursor
deallocate zm_cursor

GO

DROP TABLE TB1



查看完整回答
反對 回復 2019-01-05
  • 1 回答
  • 0 關注
  • 478 瀏覽
慕課專欄
更多

添加回答

舉報

0/150
提交
取消
微信客服

購課補貼
聯系客服咨詢優惠詳情

 幫助反饋 APP下載

慕課網APP
您的移動學習伙伴

 公眾號

掃描二維碼
關注慕課網微信公眾號