{ "programmers": [ { "firstName": "Brett", "lastName":"McLaughlin", "email": "aaaa" }, { "firstName": "Jason", "lastName":"Hunter", "email": "bbbb" }, { "firstName": "Elliotte", "lastName":"Harold", "email": "cccc" }],"authors": [ { "firstName": "Isaac", "lastName": "Asimov", "genre": "science fiction" }, { "firstName": "Tad", "lastName": "Williams", "genre": "fantasy" }, { "firstName": "Frank", "lastName": "Peretti", "genre": "christian fiction" } ], "musicians": [ { "firstName": "Eric", "lastName": "Clapton", "instrument": "guitar" }, { "firstName": "Sergei", "lastName": "Rachmaninoff", "instrument": "piano" } ] } 這樣的數據格式是怎么樣轉換的我從數據庫查出來的數據直接轉換的話是[{ "firstName": "Eric", "lastName": "Clapton", "instrument": "guitar" },{ "firstName": "Sergei", "lastName": "Rachmaninoff", "instrument": "piano" }]這樣的！因為是分開查詢三個表 ，把它組成一條json數據，應該怎么去寫
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拉丁的傳說
TA貢獻1789條經驗 獲得超8個贊
json和php數組 格式的互相轉換，參考如下：
$php_json = json_encode($json_arr); //把php數組格式轉換成 json 格式的數據
echo $php_json;
$php_json = json_decode($php_json); //再把json格式的數據轉換成php數組
print_r($php_json);
json數組
$json = '[{"id":"22","name":"33","descn":"44"}]'; //json格式的數組轉換成 php的數組
$arr = (Array)json_decode($json);
echo $arr[0]->id; //用對象的方式訪問
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