if (Statue == "success") {var x = data.split("$");var y = $("#table1");for (i = 0; i < x.length; i++) {var z = $.parseJSON(x[i]);alert(z.Good_name);var w = $("<tr><td id='check' width='6%' class='line' ><input type='checkbox' name='selected' value='" + i + "'/></td><td width='10%'id='GoodNo'><div style='width:90px;text-align:center;'>" + z.Good_number + "</div></td><td width='30%' class='bg' style='text-align:left;'id='GoodName'><div class='cart_pic'><div><a href='#' target='_blank'title='" + z.Galign='absmiddle'></a></div></td><td width='12%' id='Price'><p>商城價:<span>" + z.Price + "</span></p></td><td width='11%' id='Total' class='bg' ><b>" + z.Quanity * z.Price + "</b></td><td width='5%' id='Operator' ><a id='removeProduct'>刪除</a></td></tr>");y.append(w);$("removeProduct").click(function () {$.post("../BLL/ShopcarAjax.ashx", { "action": "remove", "id": z.Good_number }, function (txtData, txtStatue) {第二個post不工作 請高手幫幫我!
jquery post里還能再調post嗎?
慕婉清6462132
2018-10-23 08:04:34
