數據結構描述var users = [
{id: 1, username: '123', authPlayerIds: [1001, 1002, 1003]},
{id: 2, username: 'qwe', authPlayerIds: [1003, 1004, 1005]},
{id: 3, username: 'fdf', authPlayerIds: [1002, 1007, 1088]},
{id: 4, username: 'dsa', authPlayerIds: [1001, 1022, 1033]},
... // 注意: 數據在`20000`以上]需求描述計算authPlayerIds字段中的每一項(id)所出現的次數以及包含它的用戶(user)性能優先(首選)處理結束后的數據結構var authPlayers = {
'1001': [
{id: 1, username: '123'},
{id: 4, username: 'dsa'}
], '1002': [
{id: 1, username: '123'},
{id: 3, username: 'fdf'},
{id: 4, username: 'dsa'},
], '1003': [
{id: 1, username: '123'},
{id: 2, username: 'qwe'},
]
}語言及工具描述JavaScriptNode.jsLodashunderscoreasyncbluebird一切你想用的工具都可以在線急等...是時候表演真正的技術了
2 回答
搖曳的薔薇
TA貢獻1793條經驗 獲得超6個贊
var authPlayers = {};
for(var i=0;i<users.length;i++){
var use = users[i];
var useIds = users[i].authPlayerIds;
delete use.authPlayerIds;
for(var j=0;j<useIds.length;j++){
if( authPlayers[useIds[j]] == undefined ){
authPlayers[useIds[j]]=[];
authPlayers[useIds[j]].push(use);
}else{
authPlayers[useIds[j]].push(use);
}
//console.log( authPlayers[useIds[j]] )
}
}
大話西游666
TA貢獻1817條經驗 獲得超14個贊
var users = [
{id: 1, username: '123', authPlayerIds: [1001, 1002, 1003]},
{id: 2, username: 'qwe', authPlayerIds: [1003, 1004, 1005]},
{id: 3, username: 'fdf', authPlayerIds: [1002, 1007, 1088]},
{id: 4, username: 'dsa', authPlayerIds: [1001, 1022, 1033]},
]
var ret = {}
users.forEach(function(e){
var ap = e.authPlayerIds
ap.forEach(function(p){
var t = {}
if (ret[p]) {
t.id = e.id || null
t.username = e.username || null
} else {
ret[p] = []
t.id = e.id || null
t.username = e.username || null
}
ret[p].push(t)
})
})
添加回答
舉報
0/150
提交
取消